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2 years ago

Can someone help me with this question?

Mathematics

1 answer:

Likurg_2 [28]2 years ago

6 0

I’d say the answer is 72

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How to solve and what is the answer

meriva

Answer:

Step-by-step explanation:

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2 years ago

The freezer is 18c after cooling the temp. Was -12c, what's the difference?

zmey [24]

I am pretty sure 30 is the answer

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2 years ago

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When rounding to the nearest hundred, which of the following numbers round to 400?

shepuryov [24]

The answer is 423 since it's the closest number to 400 from all the numbers listed above.

The numbers 351 and 445 would also round to 400 but they are not the closest ones.

Hope it helped,

BioTeacher101

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3 years ago

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HELP!! Select the values for the domain and range of the functions graphed below.

Goryan [66]

Answer:

Graph 1

Domain = -8 =< x =< 10

Range = -9 =< f(x) =< 9

Graph 2

Domain = -1 =< x =< 5

Range = -1 =< f(x) =< 2

Explaination:

Domain means the inputed x values on the x-axis, so to make things simpler and to not write every individual x values. We write it with <, >, and =<. (you can see it as the 'width' of a graph).

Range means the output y values on the y-axis. It's like the 'height' of a graph. And also, to make things simpler and to not write every individual y values. We write it with <, >, and =< with f(x) too because f(x) = y.

3 0

2 years ago

Help pleaseeeeeeeeeeeeeeeeeeeeeee

bixtya [17]

Answer: $\bold{(1)\ \dfrac{19,683}{64}\qquad (2)\ 16}$

<u>Step-by-step explanation:</u>

(1) (12, 18, 27, ...)

The common ratio is:

$r=\dfrac{a_{n+1}}{a_n}\quad r =\dfrac{18}{12}=\boxed{\dfrac{3}{2}}\quad \rightarrow \quad r=\dfrac{27}{18}=\boxed{\dfrac{3}{2}}$

The equation is:

$a_n=a_o(r)^{n-1}\\\\Given:a_o=12,\ r=\dfrac{3}{2}\\\\\\Equation:\\a_n =12\bigg(\dfrac{3}{2}\bigg)^{n-1}\\\\\\\\9th\ term:\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{9-1}\\\\\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{8}\\\\\\.\quad =\large\boxed{\dfrac{19643}{64}}$

$(2)\qquad \bigg(\dfrac{1}{16},\dfrac{1}{8},\dfrac{1}{4},\dfrac{1}{2}\bigg)\\\\\\\text{The common ratio is}:\\\\r=\dfrac{a_{n+1}}{a_n}\quad r=\dfrac{\frac{1}{8}}{\frac{1}{16}}=\boxed{2}\quad \rightarrow \quad r=\dfrac{\frac{1}{4}}{\frac{1}{8}}=\boxed{2}$

The equation is:

$a_n=a_o(r)^{n-1}\\\\Given:a_o=\dfrac{1}{16},\ r=2\\\\\\Equation:\\a_n =\dfrac{1}{16}(2)^{n-1}\\\\\\\\9th\ term:\\a_9=\dfrac{1}{16}(2)^{9-1}\\\\\\a_9=\dfrac{1}{16}(2)^{8}\\\\\\.\quad =\large\boxed{16}$

3 0

2 years ago