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irakobra [83]
2 years ago
6

Which of the following is the equation of a line that passes through the points (1,6) and (2,1)

Mathematics
2 answers:
anastassius [24]2 years ago
5 0

Answer:

A

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

To calculate m use the slope formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (1, 6) and (x₂, y₂ ) = (2, 1)

m = \frac{1-6}{2-1} = - 5, hence

y = - 5x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (1, 6), then

6 = - 5 + c ⇒ c = 6 + 5 = 11

y = - 5x + 11 → A

TiliK225 [7]2 years ago
4 0

Answer:

y=-5x+11

Step-by-step explanation:

Given :  Points (1,6) and (2,1)

To Find : Which of the following is the equation of a line that passes through the points (1,6) and (2,1) ?

Solution:

(x_1,y_1)=(1,6)\\(x_2,y_2)=(2,1)

Now to find the equation of a line that passes through the points (1,6) and (2,1) we will use two point slope form

Two point slope form : y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)

Substitute the values

y-6=\frac{1-6}{2-1}(x-1)

y-6=-5(x-1)

y-6=-5x+5

y=-5x+11

So, Option A is true.

Hence The equation of a line that passes through the points (1,6) and (2,1) isy=-5x+11

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