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2 years ago

Csc A - sin A = A. (cos^2A) / (sinA) B. (1 - sinA) / (sinA) C. (1 - sinA) / (cosA)

Mathematics

2 answers:

igor_vitrenko [27]2 years ago

5 0

Answer:

1st option

Step-by-step explanation:

Using the identities

csc x = $\frac{1}{sinx}$

sin² x + cos²x = 1 ⇒ cos²x = 1 - sin²x

then

csc A - sinA

= $\frac{1}{sinA}$ - sinA

= $\frac{1-sin^2A}{sinA}$

= $\frac{cos^2A}{sinA}$

julsineya [31]2 years ago

4 0

Answer:

A) $\frac{cos^2A}{sinA}$

Step-by-step explanation:

$cscA-sinA\\\\\frac{1}{sinA}-sinA\\ \\\frac{1}{sinA}-\frac{sin^2A}{sinA}\\ \\ \frac{1-sin^2A}{sinA}\\ \\\frac{cos^2A}{sinA}$

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Answer:

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Read 2 more answers

Value of the derivative of g(x)=8-10Cosx at 'x=0' is?

VLD [36.1K]

Answer:

g'(0) = 0

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Function Notation

Pre-Calculus

Unit Circle

Calculus

Derivatives
Derivative Notation
The derivative of a constant is equal to 0
Derivative Property: $\frac{d}{dx} [cf(x)] = c \cdot f'(x)$
Trig Derivative: $\frac{d}{dx} [cos(x)] = -sin(x)$

Step-by-step explanation:

Step 1: Define

g(x) = 8 - 10cos(x)

x = 0

Step 2: Differentiate

Differentiate [Trig]: g'(x) = 0 - 10[-sin(x)]
Simplify Derivative: g'(x) = 10sin(x)

Step 3: Evaluate

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