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Varvara68 [4.7K]
2 years ago
15

Csc A - sin A = A. (cos^2A) / (sinA) B. (1 - sinA) / (sinA) C. (1 - sinA) / (cosA)

Mathematics
2 answers:
igor_vitrenko [27]2 years ago
5 0

Answer:

1st option

Step-by-step explanation:

Using the identities

csc x = \frac{1}{sinx}

sin² x + cos²x = 1 ⇒ cos²x = 1 - sin²x

then

csc A - sinA

= \frac{1}{sinA} - sinA

= \frac{1-sin^2A}{sinA}

= \frac{cos^2A}{sinA}

julsineya [31]2 years ago
4 0

Answer:

A) \frac{cos^2A}{sinA}

Step-by-step explanation:

cscA-sinA\\\\\frac{1}{sinA}-sinA\\ \\\frac{1}{sinA}-\frac{sin^2A}{sinA}\\ \\ \frac{1-sin^2A}{sinA}\\ \\\frac{cos^2A}{sinA}

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The solution to the system of inequalities given is: \frac{4}{3} \leq y \leq 4

<h3>What is the solutions to a system of inequalities?</h3>

The solution is the set of values that respect all conditions of the system.

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