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2 years ago

Csc A - sin A = A. (cos^2A) / (sinA) B. (1 - sinA) / (sinA) C. (1 - sinA) / (cosA)

Mathematics

2 answers:

igor_vitrenko [27]2 years ago

5 0

Answer:

1st option

Step-by-step explanation:

Using the identities

csc x = $\frac{1}{sinx}$

sin² x + cos²x = 1 ⇒ cos²x = 1 - sin²x

then

csc A - sinA

= $\frac{1}{sinA}$ - sinA

= $\frac{1-sin^2A}{sinA}$

= $\frac{cos^2A}{sinA}$

julsineya [31]2 years ago

4 0

Answer:

A) $\frac{cos^2A}{sinA}$

Step-by-step explanation:

$cscA-sinA\\\\\frac{1}{sinA}-sinA\\ \\\frac{1}{sinA}-\frac{sin^2A}{sinA}\\ \\ \frac{1-sin^2A}{sinA}\\ \\\frac{cos^2A}{sinA}$

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Steps:

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Step-by-step explanation:

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