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mote1985 [20]
3 years ago
10

How many significant figures are in the number 4005?

Mathematics
1 answer:
Natalija [7]3 years ago
7 0

Answer:

4

Step-by-step explanation:

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9

Step-by-step explanation:

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Help again please!!!!!!!!!!!!!!!!!
saveliy_v [14]
C is the best answer 

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If the area of a square field is 36sq.m .then the perimeter of the field is_​
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Answer:

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3 years ago
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What is the following quotient? StartFraction 3 StartRoot 8 EndRoot Over 4 StartRoot 6 EndRoot EndFraction.
Snowcat [4.5K]

You can simplify the given expression by taking out those factors who are perfect squares.

The simplified form  of the given expression will be  \dfrac{\sqrt{3}}{2}

<h3>How to simplify values which are under the root?</h3>

If possible, try to defactor what is inside the root.

For example, if 8 is under square root, then you can defactor 8 as made up of 2 times 2 times 2. Since 2 times 2 is perfect square, thus this can come out of the root.

Simply, some more such methods can be used to simplify these type of values.

<h3>Using the simplification method on given expression</h3>

\dfrac{3\sqrt{8}}{4\sqrt{6}} = \dfrac{3\sqrt{2 \times 2 \times 2}}{4\sqrt{6}}\\\\&#10;\dfrac{3\sqrt{8}}{4\sqrt{6}} = \dfrac{3 \times 2\sqrt{2}}{4\sqrt{6}}\\&#10;&#10;\\&#10;\dfrac{3\sqrt{8}}{4\sqrt{6}}  = \dfrac{6\sqrt{2}}{4\sqrt{6}} = \dfrac{\sqrt{6}\sqrt{2}}{4}\\\\&#10;\dfrac{3\sqrt{8}}{4\sqrt{6}}  = \dfrac{\sqrt{12}}{4} = \dfrac{\sqrt{4 \times 3}}{4} = \dfrac{\sqrt{3}}{2}

Thus, after getting simplified, the expression becomes \dfrac{\sqrt{3}}{2}

Learn more about quotient here:

brainly.com/question/16076853

7 0
2 years ago
Jenny was in charge of selling tickets to a family fun night at her school
ra1l [238]
I’ve attached my work below for #4
5) 8% is equivalent to 8 cents so each item was $1.08
Than you know he spent 16.20 so you divided
1.08/16.20 which equals 15
So he got 15 items
6) the moon is 250,000 miles away which is about driving around earth 10 times which would take 6 months (not sure about this one)

Hope this helps!
Have a nice day :)

4 0
4 years ago
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