![v_r(t)=r\cdot i(t)=(0.5\,\Omega)(0.1\sin{(20t)\,A})=0.05\sin{(20t)}\,V\\\\v_l(t)=l\cdot \dfrac{d}{dt}(i(t))=(0.010\,H)(20\cdot 0.1\cos{(20t)\,A/s})=0.02\cos{(20t)\,V}](https://tex.z-dn.net/?f=v_r%28t%29%3Dr%5Ccdot%20i%28t%29%3D%280.5%5C%2C%5COmega%29%280.1%5Csin%7B%2820t%29%5C%2CA%7D%29%3D0.05%5Csin%7B%2820t%29%7D%5C%2CV%5C%5C%5C%5Cv_l%28t%29%3Dl%5Ccdot%20%5Cdfrac%7Bd%7D%7Bdt%7D%28i%28t%29%29%3D%280.010%5C%2CH%29%2820%5Ccdot%200.1%5Ccos%7B%2820t%29%5C%2CA%2Fs%7D%29%3D0.02%5Ccos%7B%2820t%29%5C%2CV%7D)
Then the total voltage is ...
![v(t)=(0.05\sin{(20t)}+0.02\cos{(20t)})\,V\approx 0.05385\sin{(20t+0.3805)\,V}](https://tex.z-dn.net/?f=v%28t%29%3D%280.05%5Csin%7B%2820t%29%7D%2B0.02%5Ccos%7B%2820t%29%7D%29%5C%2CV%5Capprox%200.05385%5Csin%7B%2820t%2B0.3805%29%5C%2CV%7D)
The magnitude of the resultant voltage is √(.02²+.05²); the angle is arctan(.02/.05).
Answer: the sequence is to divide by 3 and it gets smaller and smaller by dividing by three I don't think there is an end to it.
Step-by-step explanation:
9/3=3
3/3=1
1/3=1/3
1/3/3=1/9
1/9/3=1/27
1/27/3=1/81
and I think you know what I mean by now right?
2x+3y=-18
3y=-2x-18
y=(-2x-18)/3
The y-intercept is the value of y when x=0 so
y-intercept=-18/3=-6, technically the point (0.-6)
The x-intercept occurs when y=0 so
(-2x-18)/3=0
-2x-18=0
-2x=18
x=-9 So the x-intercept is the point (-9,0)
So x-intercept is -9 and y-intercept is -6
the angle for a straight line is 180°. since the question gave you 100°, this means the other angle to complete the straight line is 80°. you know, 100°- 80°. then, the type of angle is corresponding angle. meaning ; the 80° angle is the same as (x+10)°. hence, to find the value of x, form an equation.
Solution:
(x + 10)° = 80°
x = 80° - 10°
x = 70°
Answer:
The same place as 1/3
Step-by-step explanation:
image for more context
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