1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
pantera1 [17]
2 years ago
7

For the function F(x) = 1/x, whose graph is shown below, what is the relative value of F(x) when the value of x is close to zero

?
A - Either a very large positive or very large negative number
B.A very small positive number
C. Only a very large positive number
D.Only a very large negative number
E.Either a very small positive or very small negative number
Mathematics
1 answer:
Serhud [2]2 years ago
5 0
Well think about it. If you divide by something less than 1, your number gets bigger.

2 \div 0.1 = 20

Same thing when it's negative, except now the answer is negative. So, if x gets really close to 0, it will be very big, or a big negative number. Remember, "getting close to 0" could mean from the negative side just as well from the positive.
You might be interested in
Find the compound interest compounded annually on rupees 2700 rate 6 ⅔% per annum and time is 2 years​
dalvyx [7]

<u>Answer:</u>

plz mark me as brainliest ...TOOK ME LONG TIME TO TYPE

answer = CI = 3108 RUPEES

<u>Step-by-step explanation:</u>

i am doing the method in which u find the simple interest of first year then second year.

SI FOR 1ST YEAR= P X R X T / 100

SI = 2700 X 20 X 2 / 3 X 100   ( RATE OF INTEREST IS 20 / 3)

SI = 108000/300

SI = 360

SI FOR SECOND YEAR =

P = 2700 + 360= 3060

SI = 3060 X 20 X 2 / 300

SI= 122400 / 300

SI = 408

COMPOUND INTEREST (CI) = PRINCIPLE + SI OF 2ND YEAR

CI = 2700 + 408

CI = 3108 RUPEES

or u can solve be the method

CI = amount - principle

Amount= principle x (change in ratio) raised to time

                                       ***************************************

6 0
3 years ago
What is the value of p+9 when p=16​
Tasya [4]

Answer:

25 :)

Step-by-step explanation:

well, if it's p+9 and you know that p=16 then you plug 16 in for p so the equation will be 16+9 and then you solve from there which is 25

4 0
2 years ago
At Mr. Hynd's ranch, there are 35 chickens and 20 cows. What is the ratio of the number of cows to the
Anton [14]
7/4 because you simplify
5 0
2 years ago
I need help please ​
Naddik [55]

Answer:

Step-by-step explanation:

7) ∠1  + 30 = 180                {linear pair}

            ∠1 = 180 - 30

            ∠1 = 150

8)  ∠2 = 30    {Vertically opposite angles are congruent}

9) In ΔLMN,

∠L + ∠N + ∠M = 180   {angle sum property of triangle}

50 + 30 + ∠M = 180

       80 + ∠M = 180

                ∠M = 180 - 80

                ∠M = 100°

10) Sum of exterior angle of a triangle equals to sum of opposite interior angles.

∠B + ∠A = ∠BCD

30 +   ∠A = 80

        ∠A  = 80 - 30

      ∠A = 50

4 0
2 years ago
Read 2 more answers
Vanessa built an enclosed area in the shape of a square in her backyard for her dogs. She used an outside wall of the garage for
sveticcg [70]
It is 1 yard squared or 9 feet squared
8 0
2 years ago
Read 2 more answers
Other questions:
  • A wheelchair ramp runs 36 inches and rises 3 inches. What is the rate of change?
    7·2 answers
  • Just 13 a and b please and thank you
    7·1 answer
  • Find all roots: x^3-7x^2-12x = 0
    6·1 answer
  • What is the answer to |4r−12| , if r&lt;3?
    5·1 answer
  • What is the measure of ZWX?
    5·1 answer
  • Solve this ASAP 12/y equals 4/3
    7·1 answer
  • Complete the equation.<br> (4x)−2(4x)3(4x)9=(4x)
    10·1 answer
  • Amy and Darren each solved the following system of equations using a different method
    7·1 answer
  • ayuda porfavor cuanto es h+3cm=? y cuanto es b+4cm=? y cual seria el resustado de las dos calculacion
    13·1 answer
  • a clothing store has sing has the sign shown is in the shop windoe pani sees the sing and want s to buy 3 shirts
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!