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3 years ago

The sum of five times h and twice g is equal to 23

Mathematics

1 answer:

Mariana [72]3 years ago

8 0

answer: 5h + 2g = 23

to solve problems like this, pull apart the equation.

the sum of five times h and twice g is equal to 23

so, we know we're going to be adding two terms, what are they?

five times h and twice g

so, 5h + 2g.

what does it equal?

the sum of five times h and twice g is equal to 23

this means 5h + 2g = 23

i hope this helped and have a great day! if you need any further assistance with this specific question or i made any mistakes, please let me know!

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Sum of 1/2*3 +1/3*4 +1/4*5 ..1/99*100

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Answer:

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=(1−12)+(13−14)+(15−16)+⋯+(199−1100)

=(1+13+15+17+⋯+199)−(12+14+16+⋯+1100)

=(1+13+15+17+⋯+199)−12(1+12+13+⋯+150)

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3 years ago

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3 years ago

How do I put these equations into vertex form?

sergiy2304 [10]

Answer:

Step-by-step explanation:

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3 years ago

51 POINTS!!!!!! (3x-y=2)*2

algol [13]

Answer:

Solving for the variable, x: $x = \frac{1}{3}y + \frac{2}{3}$

Solving for the variable, y: $y = 3x - 2$

Step-by-step explanation:

IF:

You are solving for the variable, x. Note the equal sign, what you do to one side, you do to the other. Isolate the variable, x. First, follow PEMDAS, then do the opposite of PEMDAS.

First, distribute 2 to all terms within the parenthesis:

(3x - y = 2) * 2 = (6x - 2y = 4)

Next, solve for x. Add 2y to both sides:

6x - 2y (+2y) = 4 (+2y)

6x = 4 + 2y

Next, divide 6 from both sides:

(6x)/6 = (4 + 2y)/6

x = (2y)/6 + (4)/6

x = (1/3)y + (2/3)

IF:

You are solving for the variable, y. Note the equal sign, what you do to one side, you do to the other. Isolate the variable, y. First, follow PEMDAS, then do the opposite of PEMDAS.

First, distribute 2 to all terms within the parenthesis:

(3x - y = 2) * 2 = (6x - 2y = 4)

Next, solve for y. Subtract 6x from both sides:

6x - 2y = 4

6x (-6x) - 2y = 4 (-6x)

-2y = -6x + 4

Then, divide -2 from both sides:

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y = 3x + (-2)

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7 0

3 years ago