Answer:
If you've learnt sin(A+B) = sinAcosB + cosAsinB,
sin(4u)
= sin(2u+2u)
= sin(2u)cos(2u) + cos(2u)sin(2u)
= 2 sin(2u) cos(2u).
4:1 should be your answer I might be dumb♀️
Answer:
The area of the remaining board is [(L × B) - (l × b)].
Step-by-step explanation:
Suppose the bigger rectangle is labelled as ABCD and the smaller rectangle is labelled as PQRS.
Consider that the length and breadth of the bigger rectangle are L and B respectively. And the length and breadth of the bigger rectangle are l and b respectively.
The area of any rectangle is:
Area = Length × Breadth
The area of the bigger rectangle is:
Area of ABCD = L × B
The area of the smaller rectangle is:
Area of PQRS = l × b
Then the area of the remaining board will be:
Area of remaining board = Area of ABCD - Area of PQRS
= (L × B) - (l × b)
Thus, the area of the remaining board is [(L × B) - (l × b)].
Answer:
N/A
Step-by-step explanation:
Reason: Not enough information
