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3 years ago

$1.12 for 8.2 ounces

2 answers:

6 0

$1.12 for 8.2 ounces means that u would pay around 0.12 per ounce but keep in mind u still have the .2 ounces.
Hope this helps!!

Leno4ka [110]3 years ago

3 0

What about it
what is the question

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I need fast help with step by step<br> <img src="https://tex.z-dn.net/?f=%5Cint%5Climits%5E2_1%20%7B%5Cfrac%7B3x-1%7D%7Bx%2B1%7D

Ganezh [65]

Answer:

1.38 to the nearest hundredth.

Step-by-step explanation:

Dividing:

x + 1 ) 3x - 1 ( 3

3x + 3

-4

so (3x - 1) / (x + 1) = 3 - 4 / x+ 1

Integral of (3 - 4 / x+1 ) = 3x - 4 ln(x + 1)

Between limits of 1 and 2 we have:

(3(2) - 4 ln 3) - (3 - 4 ln2)

= 1.6056 - 0.2274

= 1.3782.

5 0

4 years ago

7n2 + 5 = 453<br> Solve the quadratic function

Reptile [31]

7n^2 + 5 = 453

Subtract 5 from both sides:

7n^2 = 448

Divide both sides by 7:

N^2 = 64

Take the square root of both sides:

N = 8

8 0

4 years ago

Read 2 more answers

A safety regulation states that the maximum angle of elevation for a rescue ladder is 72°. A fire department's longest ladder is

Julli [10]

Answer:

The maximum safe rescue height is 104.6 feet above the height of the ground.

Step-by-step explanation:

Consider a triangle ABC where C is the point where the rescue ladder is standing and AB be the building and Ladder making an angle of 72° as shown.

We have to find the height of the building.

Let x be the height of building

Using Trigonometric ratio,

$\sin C=\frac{\text{Perpendicular}}{\text{Hypotenuse}}$

$\sin 72^{\circ}=\frac{AB}{BC}$

$\sin 72^{\circ}=\frac{x}{110}$

$x=110 \times \sin 72^{\circ}$

$x=104.6$

So, the maximum safe rescue height is 104.6 feet above the height of

the ground.

5 0

3 years ago

Read 2 more answers

Jenna is running a trail that is 8 4/7 miles long. If she has finished running 5/9 of the distance, about how far has she run?

Varvara68 [4.7K]

Answer:

Jenna has run the distance of $\frac{100}{21}$ miles .

Step-by-step explanation:

The Distance for the trail = 8 $\frac{4}{7}$ = $\frac{56+4}{7}$

Or , Distance = $\frac{60}{7}$ miles

The distance cover by Jenna = $\frac{5}{9}$ miles of the distance

I.e The distance cover by Jenna = $\frac{5}{9}$ × $\frac{60}{7}$

Or, The distance cover by Jenna = $\frac{100}{21}$ miles

Hence Jenna has run the distance of $\frac{100}{21}$ miles . Answer

5 0

3 years ago

Which of the following is the standard equation of the ellipse with vertices at (1,0) and (27,0) and an eccentricity of 5/13?

Dovator [93]

The equation of the elipse is given by:

$\frac{(x - 14)^2}{169} + \frac{y^2}{144} = 1$

The equation of an elipse of center $(x_0, y_0)$ is given by:

$\frac{(x - x_0)^2}{a^2} + \frac{(y - y_0)^2}{b^2} = 0$

Values a and b are found according to the <u>vertices and the eccentricity</u>.

It has vertices at (1,0) and (27,0), thus:

$x_0 = \frac{27 + 1}{2} = 14$

$y_0 = \frac{0 + 0}{2} = 0$

$a = \frac{27 - 1}{2} = 13$

$a^2 = 169$

It has eccentricity of $\frac{5}{13}$ , thus:

$\frac{5}{13} = \frac{c}{a}$

$\frac{5}{13} = \frac{c}{13}$

$c = 13$

Thus, b is given according to the following equation:

$c^2 = a^2 - b^2$

$b^2 = a^2 - c^2$

$b^2 = 169 - 25$

$b = \sqrt{144}$

$b = 12$

The equation of the elipse is:

$\frac{(x - 14)^2}{169} + \frac{y^2}{144} = 1$

A similar problem is given at brainly.com/question/21405803

3 0

3 years ago