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kozerog [31]
2 years ago
13

$1.12 for 8.2 ounces

Mathematics
2 answers:
sukhopar [10]2 years ago
6 0
$1.12 for 8.2 ounces means that u would pay around 0.12 per ounce but keep in mind u still have the .2 ounces.
Hope this helps!!
Leno4ka [110]2 years ago
3 0
What about it
what is the question


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Can anyone help? with these probelms.
vredina [299]

Answer:

Denise = total cost $3,345.00 per mile cost is 0.3185 or 32 cents per mile

Total Lease cost = $15,516

Step-by-step explanation:

5 0
3 years ago
35 points!! How much does a fish weigh if its tail weighs 4 kilograms, it's head weighs as much as it's tail and half its body,
NeX [460]

Let t, h, b represent the weighs of tail, head, and body, respectively.

t = 4 . . . . given

h = t + b/2 . . . . the head weighs as much as the tail and half the body

b/2 = h + t . . . . half the body weighs as much as the head and tail

_____

Substituting for b/2 in the second equation using the expression in the third equation, we have

... h = t + (h + t)

Subtracting h from both sides gives

... 0 = 2t . . . . . . in contradiction to the initial statement about tail weight.

Conclusion: there's no solution to the problem given here.

4 0
3 years ago
the perimeter of the rectangle below is 98 units. Find the length of CD. Write your answer without variables. cd=4x+3 cb=5x+1
zimovet [89]

2(4x + 3) + 2(5x + 1) = 98 \\ 8x + 6 + 10x + 2 = 98 \\ 18x + 8 = 98 \\ 18x = 90 \\  x = 5
Substitute x with 5,

CD =
4x + 3 \\  = 4(5) + 3 \\  = 20 + 3 \\  = 23
CD = 23 units

Hope this helps.
7 0
3 years ago
Read 2 more answers
on an airplane,there are two seats on the left side in each row and three seats on the right side.There are 90 seats on the righ
pantera1 [17]
Left side: (equation) 2/x=3/90 (multiply them together by cross multiplying. 90x2 divided by 3)
=60

Altogether: 90 (right) + 60 (left) =150 seats in total 
                          
4 0
3 years ago
Read 2 more answers
Please help! I don't understand how to solve this problem
Ilia_Sergeevich [38]

Using the z-distribution, a sample of 142,282 should be taken, which is not practical as it is too large of a sample.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm z\frac{\sigma}{\sqrt{n}}

The margin of error is:

M = z\frac{\sigma}{\sqrt{n}}

In which:

  • \overline{x} is the sample mean.
  • z is the critical value.
  • n is the sample size.
  • \sigma is the standard deviation for the population.

Assuming an uniform distribution, the standard deviation is given by:

S = \sqrt{\frac{(4 - 0)^2}{12}} = 1.1547

In this problem, we have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

The sample size is found solving for n when the margin of error is of M = 0.006, hence:

M = z\frac{\sigma}{\sqrt{n}}

0.006 = 1.96\frac{1.1547}{\sqrt{n}}

0.006\sqrt{n} = 1.96 \times 1.1547

\sqrt{n} = \frac{1.96 \times 1.1547}{0.006}

(\sqrt{n})^2 = \left(\frac{1.96 \times 1.1547}{0.006}\right)^2

n =  142,282.

A sample of 142,282 should be taken, which is not practical as it is too large of a sample.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

8 0
1 year ago
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