What is the surface area of a cylindrical ring where the diameter of the cross section is 6.3 in and the center line has a lengt
h of 48 in? A. 529.86 in2 B. 256.22 in2 C. 950.02 in2 D. 849.73 in2
2 answers:
Answer: Option 'C' is correct.
Step-by-step explanation:
Since we have given that
Diameter of cylinder = 6.3 inches
Radius of cylinder is given by

Height of cylinder = 48 in.
As we know the "Surface area of cylinder":

Hence, Option 'C' is correct.
The surface area of the cylindrical ring is given by
πdh
where d is the diameter and h is the height:
π•6.3•48 = 950.02
The answer is C. 950.02 in^2
You might be interested in
Answer: D
Step-by-step explanation:
Answer:
diameter
Step-by-step explanation:
Answer:
321312313123
Step-by-step explanation:
because ur gay
X=f
x×1+1-2+3=3234557901028292