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3 years ago

Which of the following correctly uses absolute value to show the distance between -70 and 13?

1 answer:

5 0

The answer is 4 i think? because since -70 is negative and you're adding 13 but you're actually subtracting so ig 4 (sorry if my reasoning doesn't make sense)

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Abby is helping the art teacher pass out paint. She finds 9 full jugs of paint on a shelf. Each jug holds 3 liters. How much pai

sashaice [31]

27 liters of paint... 3 liters per jug a total of 9 jugs meaning 9x3=27

6 0

3 years ago

the entire bag is about 800 calories. one serving is 1/5 of the bag. how many calories is in one serving?

Svetradugi [14.3K]

Answer: 160 calories

Step-by-step explanation:

6 0

3 years ago

Mia buys a watch while visiting her cousin in California. The sales tax in California is 10.25%.

netineya [11]

Answer:

$400

Step-by-step explanation:

<u>Let the watch price be x, then we have:</u>

10.25% of x = 41 or
0.1025x = 41

<u>Solve for x</u>

x = 41/0.1025
x = 400

8 0

2 years ago

Read 2 more answers

Allied Corporation is trying to sell its new machines to Ajax. Allied claims that the machine will pay for itself since the time

kvasek [131]

Answer:

z(s) is in the acceptance region. We accept H₀ we did not find a significantly difference in the performance of the two machines therefore we suggest not to buy a new machine

Step-by-step explanation:

We must evaluate the differences of the means of the two machines, to do so, we will assume a CI of 95%, and as the interest is to find out if the new machine has better performance ( machine has a bigger efficiency or the new machine produces more units per unit of time than the old one) the test will be a one tail-test (to the left).

New machine

Sample mean x₁ = 25

Sample variance s₁ = 27

Sample size n₁ = 45

Old machine

Sample mean x₂ = 23

Sample variance s₂ = 7,56

Sample size n₂ = 36

Test Hypothesis:

Null hypothesis H₀ x₂ - x₁ = d = 0

Alternative hypothesis Hₐ x₂ - x₁ < 0

CI = 90 % ⇒ α = 10 % α = 0,1 z(c) = - 1,28

To calculate z(s)

z(s) = ( x₂ - x₁ ) / √s₁² / n₁ + s₂² / n₂

s₁ = 27 ⇒ s₁² = 729

n₁ = 45 ⇒ s₁² / n₁ = 16,2

s₂ = 7,56 ⇒ s₂² = 57,15

n₂ = 36 ⇒ s₂² / n₂ = 1,5876

√s₁² / n₁ + s₂² / n₂ = √ 16,2 + 1.5876 = 4,2175

z(s) = (23 - 25 )/4,2175

z(s) = - 0,4742

Comparing z(s) and z(c)

|z(s)| < | z(c)|

z(s) is in the acceptance region. We accept H₀ we did not find a significantly difference in the performance of the two machines therefore we suggest not to buy a new machine

The very hight dispersion of values s₁ = 27 is evidence of frecuent values quite far from the mean

3 0

3 years ago

The p-value for a one-sided test of the population proportion is 0.0513. Which of

uysha [10]

Using the equation of the test statistic, it is found that with an increased sample size, the test statistic would decrease and the p-value would increase.

<h3>How to find the p-value of a test?</h3>

It depends on the test statistic z, as follows.

For a left-tailed test, it is the area under the normal curve to the left of z, which is the <u>p-value of z</u>.

For a right-tailed test, it is the area under the normal curve to the right of z, which is <u>1 subtracted by the p-value of z</u>.

For a two-tailed test, it is the area under the normal curve to the left of -z combined with the area to the right of z, hence it is <u>2 multiplied by 1 subtracted by the p-value of z</u>.

In all cases, a higher test statistic leads to a lower p-value, and vice-versa.

<h3>What is the equation for the test statistic?</h3>

The equation is given by:

$t = \frac{\overline{X} - \mu}{\frac{s}{\sqrt{n}}}$

The parameters are:

$\overline{X}$ is the sample mean.

$\mu$ is the tested value.

s is the standard deviation.

n is the sample size.

From this, it is taken that if the sample size was increased with all other parameters remaining the same, the test statistic would decrease, and the p-value would increase.

You can learn more about p-values at brainly.com/question/26454209

3 0

2 years ago