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gavmur [86]
3 years ago
9

The square root of 136 is between which two whole numbers?

Mathematics
2 answers:
n200080 [17]3 years ago
3 0
The square root of 136 is between 11 and 12. Hope I helped!
kotykmax [81]3 years ago
3 0
The square root is between 11 and 12 but closer to 12. 
Hope this helps! 
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For the partial Wheel of Emotions below, determine the area of each petal’s sector of the inner circle, if the radius of the ent
Serga [27]

Okay, here we have this:

Considering the provided figure, we are going to calculate the requested area, so we obtain the following:

So from the given information we have:

Area of the wheel = Area of the inner circle + Area of the ring

And since the area of the inner circle and the ring are equal, we have:

Area of the wheel = Area of the inner circle + Area of the inner circle

Area of the wheel = 2*Area of the inner circle

Remember that the area of a circle is:

Area of the wheel = π r^2

So substituting:

2*Area of the inner circle=π r^2

Area of the inner circle=(π r^2)/2

And the area of each petal of the inner circle is:

Area of each petal’s sector of the inner circle=Area of the inner circle / number of petals

Area of each petal’s sector of the inner circle=((π r^2)/2) / number of petals

Area of each petal’s sector of the inner circle=((π r^2)/2) / 8

So finally replacing with the given information:

Area of each petal’s sector of the inner circle=((π* (6cm)^2)/2) / 8

Area of each petal’s sector of the inner circle=((π* 36cm^2)/2) / 8

Area of each petal’s sector of the inner circle=((36π cm^2)/2) / 8

Area of each petal’s sector of the inner circle=(18π cm^2) / 8

Area of each petal’s sector of the inner circle=18π/8 cm^2

Area of each petal’s sector of the inner circle=2.25π cm^2

Finally we obtain that the Area of each petal’s sector of the inner circle is 2.25π cm^2.

7 0
1 year ago
Someone plssss help
-BARSIC- [3]
Your answer is 37%
hope this helps
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Answer:

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lilavasa [31]

Answer:

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Step-by-step explanation:

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dexar [7]
10 in the first power
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