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2 years ago

What is the Compound interest on a 10,000 investment the earns 6% compound monthlyfor5 years

Mathematics

1 answer:

Vlad1618 [11]2 years ago

8 0

Answer:

The total compound interest is $3,488.50, I hope I helped explain how to find total compound interest

Step-by-step explanation:

So the formula for this would be:

A = P(1+r/n)^nt

A = the amount of your principal plus interest, which is the total

P = stands for the principal, which is your original amount invested

r = shows the interest rate in decimal form

n = stands for the number of compounding periods

So to solve for the compound interest we would plug in our numbers in replacement for the letters

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100x+300y=1.200<br> (2/3x+10)/100=(y+20)/300

AlexFokin [52]

Answer:

x= -4.284 and y= 1.432

Step-by-step explanation:

5 0

3 years ago

Diameter=10.5 in . Determine the area of each circle. Use 3.14 or 22/7 for pie . Round to the nearest tenth.

zloy xaker [14]

Answer:

86.5 square inches

Step-by-step explanation:

Area of circle: pi*r^2

first find the radius

10.5in /2= 5.25in

find the square

5.25^2=27.5625

multiply with pi

27.5625*3.14=86.54625

rounded 86.5 in

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2 years ago

Write an expression for: the product of 4 and a number. Use x as the variable. Who ever gets it correct first gets brainliest.

maksim [4K]

X(4*1) because I’m just doing what I’m told.

7 0

2 years ago

Use the rule for y= -6x +8 to find the output if the input is x=20

lisov135 [29]

Answer:

The output of the function y = -6x + 8 when the input is x = 20 is -112.

Step-by-step explanation:

y = -6x + 8

Input the value x = 20.

y = -6(20) + 8

Multiply -6 and 20.

y = -120 + 8

Add -120 and 8.

y = -112.

8 0

3 years ago

In the adjoining figure, XY = XZ . YQ and ZP are the bisectors of <img src="https://tex.z-dn.net/?f=%20%5Cangle" id="TexFormula1

svetlana [45]

Answer:

See Below.

Step-by-step explanation:

Statements: Reasons:

$1)\, XY=XZ$ Given

$2) \text{ $ m\angle Y= m\angle Z$}$ Isosceles Triangle Theorem

$\displaystyle 3) \text{ $m\angle Y=m\angle XYQ + \angle QYZ$}$ Angle Addition

$\displaystyle 4)\text{ $YQ$ bisects $\angle XYZ$}$ Given

$5) \text{ $m\angle XYQ=m\angle QYZ$}$ Definition of Bisector

$\displaystyle 6)\text{ $m\angle Y=2m\angle QYZ$}$ Substitution

$7)\text{ $m\angle Z=m\angle XZP+m\angle PZY$}$ Angle Addition

$8)\text{ $ZP$ bisects $\angle XZY$}$ Given

$\displaystyle 9) \text{ $m\angle XZP=m\angle PZY$ }$ Definition of Bisector

$\displaystyle 10) \text{ $ m\angle Z = 2m\angle PZY $}$ Substitution

$11)\text{ } 2m\angle QYZ=2m\angle PZY$ Substitution

$12)\text{ }m\angle QYZ=m\angle PZY$ Division Property of Equality

$13)\text{ } YZ=YZ$ Reflexive Property

$14)\text{ } \Delta YZP\cong\Delta ZYQ$ Angle-Side-Angle Congruence*

$15)\text{ } YQ=ZP$ CPCTC

*For clarification:

∠Y = ∠Z

YZ = YZ (or ZY)

∠PZY = ∠QYZ

So, Angle-Side-Angle Congruence:

ΔYZP is congruent to ΔZYQ

5 0

3 years ago

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