Rolling an 11:
n(A): 6&5, 5&6
n(A) = 2
Rolling a 5:
n(B): 1&4, 4&1, 3&2, 2&3
n(B) = 4
n(A) + n(B) = 4 + 2 = 6
Answer:Yes
Step-by-step explanation:
5×3=15. 9×3=27
Use the distributive property
10-6-4x=0
4-4x=0
Answer:
in-control
Step-by-step explanation:
basically, their are 2 types of control charts delineated:
1) <u>uni-variate control chart</u> : shows one quality characteristic
2)<u>multivariate control chart</u> : shows 2 or more than two quality characteristics
in statistics, we have "<em>upper control limi</em>t" and "<em>lower control limit</em>".
if the system/variables are within these limits it is 'in-control' other wise 'out of control'
<u>in-control</u><u> </u>says that all dots are within control limit and they have random pattern.
Perimeter of Figure = Perimeter of 2 semicircles + Measures of two straight line
P = 2(πr) + 2*x
P = 2*3.14*7 + 2*13
P = 43.96 + 26
P = 69.96 m
In short, Your Answer would be: Option C
Hope this helps!
