Start with the parentheses
Answer:
The midsegment is one-half the length of the base
Let X be the random variable denoting the number of successful throws.
Here X~ Binomial Distribution with n = 5 and p = 0.80.
the probability of her missing 3 (or more) free throws out of 5
= P ( X ≤ 2)
= P (X= 0) + P(X= 1) + P(X= 2)
=0.00032 + 0.0064 + 0.0512
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= 0.05792
I hope my answer has come to your help. God bless and have a nice day ahead!
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Approximately 42% of the specials was salmon filets.
