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Mademuasel [1]
3 years ago
6

At a play the kids changed into four different costumes it took them 1.35 minutes to change each time and one break that was 5 t

imes as long as the costume changes. What is the question that is asked,what is the hidden question,and what is the answer to the problem?
Mathematics
2 answers:
Ray Of Light [21]3 years ago
8 0
0.27 and the missing question is how long did it take them to change
Tomtit [17]3 years ago
6 0
Well the hidden question is that how much time did it take for them to change including the break but I'm not sure what the broad question is.
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Solve the formula for h: A=1/2bh+3
olga55 [171]

cross multiply the equation to give you

1= a(2bh+3)

divide both sides by a(2b+3)

answer is 1/2ab+3 = h


5 0
3 years ago
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A person is shopping for cereal, oranges, and eggs at a grocery store.
Romashka [77]
I got b have a good day :)
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2 years ago
The arithmetic sequence a; is defined by the formula:
Morgarella [4.7K]

Answer:

The sum of the first 650 terms of the given arithmetic sequence is 2,322,775

Step-by-step explanation:

The first term here is 4

while the nth term would be ai = a(i-1) + 11

Kindly note that i and 1 are subscript of a

Mathematically, the sum of n terms of an arithmetic sequence can be calculated using the formula

Sn = n/2[2a + (n-1)d)

Here, our n is 650, a is 4, d is the difference between two successive terms which is 11.

Plugging these values, we have

Sn = (650/2) (2(4) + (650-1)11)

Sn = 325(8 + 7,139)

Sn = 325(7,147)

Sn = 2,322,775

6 0
3 years ago
What is 0.000025(800)^2 - 0.04(800) +40..?
Scilla [17]

Answer:

24

Step-by-step explanation:

6 0
2 years ago
Determine the number of possible triangles, ABC, that can be formed given angle A = 30°, a = 4, and b = 6.
Sophie [7]

Answer:

Step-by-step explanation:

Alright, lets get started.

using Sine Law,

\frac{sinA}{a}=\frac{sinB}{b}

\frac{sin30}{4}=\frac{sinB}{6}

sinB=0.75

angle B = 48.6

Another angle will be

angle B' = 180-48.6 = 131.4

considering angle B, angle C = 180 - (48.6+30)=101.4

considering angle B', angle C' = 180-(131.4+30)=18.6

\frac{sinA}{a}=\frac{sinC}{c}

\frac{sin30}{4}=\frac{sin101.4}{c}

c = 7.84

Similarly, finding c'

\frac{sinA}{a}=\frac{sinC'}{c'}

\frac{sin30}{4}=\frac{sin18.6}{c'}

c'=2.55

Hence two triangles are possible with below details:  :   Answer

A = 30, B = 48.6, C = 101.4, c = 7.84

A = 30, B' = 131.4, C' = 18.6, c' = 2.55

Hope it will help :)

5 0
2 years ago
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