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snow_lady [41]
4 years ago
7

Evaluate x^2-2x+2 where x=1+i

Mathematics
1 answer:
KIM [24]4 years ago
8 0

x^2 - 2x + 2

x = 1 + i

(1 + i)^2 - 2(1 + i) + 2

<em><u>Distributive property.</u></em>

(1 + i)(1 + i) - 2 - 2i + 2

<em><u>Continue distributive property on left side.</u></em>

1 + i + i + i^2 - 2 - 2i + 2

<em><u>Combine like terms.</u></em>

1 + 2i + i^2 - 2 - 2i + 2

1 + i^2

<em><u>i^2 can be interpreted as -1.</u></em>

1 - 1 = 0

The expression is equal to 0.

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