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Brut [27]
3 years ago
7

Please prove the following trigonometric identity.​

Mathematics
1 answer:
Brums [2.3K]3 years ago
3 0

Step-by-step explanation:

solution:- from LHS 1-cos²x/sinx

∵ 1-cos²x = sin²x

∴ sin²x /sinx = sinx

from RHS tanx × cosx

∵tanx = sinx×cosx

∴ sinx/ cosx × cosx = sinx

Since, LHS = RHS proved ___

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algol13

Answer:  The required answers are

(a) the slope of the given line is -\dfrac{3}{7}.

(b) y-intercept exists and is equal to 6.

(c) the slope-intercept form of the line is y=-\dfrac{3}{7}x+6.

Step-by-step explanation:  We are given the following linear equation in two variables :

3x+7y=42~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

We are to :

(a) determine the slope,

(b) determine the y-intercept, if exists

and

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We know that

The SLOPE_INTERCEPT form of the equation of a straight line is given by

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From equation (i), we have

3x+7y=42\\\\\Rightarrow 7y=-3x+42\\\\\Rightarrow y=\dfrac{-3x+42}{7}\\\\\\\Rightarrow y=-\dfrac{3}{7}x+6.

Comparing with the slope-intercept form, we get

\textup{slope, m}=-\dfrac{3}{7},\\\\\\\textup{y-intercept, c}=6.

Thus,

(a) the slope of the given line is -\dfrac{3}{7}.

(b) y-intercept exists and is equal to 6.

(c) the slope-intercept form of the line is y=-\dfrac{3}{7}x+6.

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3 years ago
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Answer:

Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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