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3 years ago

9

A ray is a portion of a line that begins at a point and extends endlessly in one direction.

1 answer:

viva [34]3 years ago

4 0

Answer: T

Step-by-step explanation:

cuz i practice geometry.

You might be interested in

A 60 - kilogram person stands on a compression spring . The spring constant is 2500 Newtons per meter .

insens350 [35]

<h2>Answer:0.2352 $m$ </h2>

Step-by-step explanation:

Let the mass of the person be $m$ .

Let the spring constant be $k$ .

Let the displacement in spring be $x$

Let the acceleration due to gravity be $g$

As it is given that the person just stands,the forces are balanced.

So, $mg=kx$

Given,

$m=60Kg\\k=2500Nm^{-1}\\g=9.8ms^{-2}$

$60\times 9.8=2500\times x\\x=\frac{588}{2500}=0.2352m$

6 0

3 years ago

artcher [175]

The answer will be 1/40

4 0

3 years ago

Read 2 more answers

6570 ÷ 16 <br><br><br>410<br><br><br>410 1/16<br><br><br>410 3/8<br><br><br>410 5/8

UNO [17]

Answer:

Exact Form:

3285

8

Decimal Form:

410.625

Mixed Number Form:

410

5

8

thats what i got i hope this helps

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Arjun sells handmade ceramic mugs he Mark's them up by 60% to make a profit they cost $8 in materials how much do this mugs cost

Reptile [31]

Answer:

$12.80

Step-by-step explanation:

Before markup: $8

After markup: $8 x 160% = $12.80

This is a topic on percentage. If you wish to explore more into this topic you can give me a follow on Instagram (learntionary). I've uploaded this topic's notes and will continue to upload more with tips as well!

6 0

2 years ago

I need help with my math homework. The questions is: Find all solutions of the equation in the interval [0,2π).

Aleksandr-060686 [28]

Answer:

$\frac{7\pi}{24}$ and $\frac{31\pi}{24}$

Step-by-step explanation:

$\sqrt{3} \tan(x-\frac{\pi}{8})-1=0$

Let's first isolate the trig function.

Add 1 one on both sides:

$\sqrt{3} \tan(x-\frac{\pi}{8})=1$

Divide both sides by $\sqrt{3}$ :

$\tan(x-\frac{\pi}{8})=\frac{1}{\sqrt{3}}$

Now recall $\tan(u)=\frac{\sin(u)}{\cos(u)}$ .

$\frac{1}{\sqrt{3}}=\frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}}$

or

$\frac{1}{\sqrt{3}}=\frac{-\frac{1}{2}}{-\frac{\sqrt{3}}{2}}$

The first ratio I have can be found using $\frac{\pi}{6}$ in the first rotation of the unit circle.

The second ratio I have can be found using $\frac{7\pi}{6}$ you can see this is on the same line as the $\frac{\pi}{6}$ so you could write $\frac{7\pi}{6}$ as $\frac{\pi}{6}+\pi$ .

So this means the following:

$\tan(x-\frac{\pi}{8})=\frac{1}{\sqrt{3}}$

is true when $x-\frac{\pi}{8}=\frac{\pi}{6}+n \pi$

where $n$ is integer.

Integers are the set containing {..,-3,-2,-1,0,1,2,3,...}.

So now we have a linear equation to solve:

$x-\frac{\pi}{8}=\frac{\pi}{6}+n \pi$

Add $\frac{\pi}{8}$ on both sides:

$x=\frac{\pi}{6}+\frac{\pi}{8}+n \pi$

Find common denominator between the first two terms on the right.

That is 24.

$x=\frac{4\pi}{24}+\frac{3\pi}{24}+n \pi$

$x=\frac{7\pi}{24}+n \pi$ (So this is for all the solutions.)

Now I just notice that it said find all the solutions in the interval $[0,2\pi)$ .

So if $\sqrt{3} \tan(x-\frac{\pi}{8})-1=0$ and we let $u=x-\frac{\pi}{8}$ , then solving for $x$ gives us:

$u+\frac{\pi}{8}=x$ ( I just added $\frac{\pi}{8}$ on both sides.)

So recall $0\le x$ .

Then $0 \le u+\frac{\pi}{8}$ .

Subtract $\frac{\pi}{8}$ on both sides:

$-\frac{\pi}{8}\le u$

Simplify:

$-\frac{\pi}{8}\le u$

$-\frac{\pi}{8}\le u$

So we want to find solutions to:

$\tan(u)=\frac{1}{\sqrt{3}}$ with the condition:

$-\frac{\pi}{8}\le u$

That's just at $\frac{\pi}{6}$ and $\frac{7\pi}{6}$

So now adding $\frac{\pi}{8}$ to both gives us the solutions to:

$\tan(x-\frac{\pi}{8})=\frac{1}{\sqrt{3}}$ in the interval:

$0\le x$ .

The solutions we are looking for are:

$\frac{\pi}{6}+\frac{\pi}{8}$ and $\frac{7\pi}{6}+\frac{\pi}{8}$

Let's simplifying:

$(\frac{1}{6}+\frac{1}{8})\pi$ and $(\frac{7}{6}+\frac{1}{8})\pi$

$\frac{7}{24}\pi$ and $\frac{31}{24}\pi$

$\frac{7\pi}{24}$ and $\frac{31\pi}{24}$

5 0

3 years ago