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3 years ago

For how many positive integers n is it possible to have a triangle with side lengths five, 12, and n

Mathematics

1 answer:

Andre45 [30]3 years ago

8 0

Step-by-step explanation:

you know, a single side cannot be longer than the other 2 sides combined.

otherwise, the triangle cannot "close".

so, it starts with 12 cannot be longer than 5 + n.

therefore, n must be at least 7.

and n cannot be longer than 5+12 = 17

7 and 17 I would normally rule out a well, because in these cases the triangle would just be a flat line, when the 3rd side is as long as the other 2 combined.

so, in reality for a real, visible triangle, the range of valid values is 8 .. 16.

that is 9 positive integer values.

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Answer:

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Step-by-step explanation:

We can solve this by using integral by parts:

Let

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$du=(1/x)dx$ $v=lnx$

$\int\limits {lnx/x} \, dx = (lnx)^2-\int\limits {lnx/x} \, dx$

We can add

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Step-by-step explanation:

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3 years ago

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Solnce55 [7]

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<h3>Lines and angle</h3>

Find the diagram attached

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Read 2 more answers

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Oksi-84 [34.3K]

For this case we have that by definition, the equation of a line of the slope-intersection form is given by:

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While the point-slope equation of a line is given by:

$y-y_ {0} = m (x-x_ {0})$

Where:

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In this case we have a line through:

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ANswer:

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