The least number of buses needed to carry 710 passengers is 5.
Option A)5 is the correct answer.
<h3>What is the least number of buses needed to carry 710 passengers? </h3>
Given that;
- Number of passengers n = 710
- Least number of buses need B = ?
To get the least number of buses, we say;
Number of buses B = 710 ÷ 150
Number of buses B = 4.7 ≈ 5
The least number of buses needed to carry 710 passengers is 5.
Option A)5 is the correct answer.
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The answer is the first choice.
Answer:
t + 12 = s
Step-by-step explanation:
t (Megan's trophies) + 12 = s (Sebastian's trophies)
I think its 6000 am not sure am just sayin bruh
The computer would cost $1020.
$35 x 12 = 420
$420 + $600 = $1020
