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3 years ago

Which equations are equal to this equation? Select all that apply.

Mathematics

2 answers:

o-na [289]3 years ago

8 0

One if them equals b and the other one is c

Andrews [41]3 years ago

5 0

Answer:

The answer is A and D because after I took the test it showed me that I got it right. Answer: A. 56 + 8x = 80. D. 2x = 6.

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1/3 of students at a school are boys. If there are 600 students at the school, how many are girls?

Temka [501]

Answer:

200 students are boys and rest of 400 are girls

Step-by-step explanation:

Given that:

Total students = 300

1/3 students of total are boys

so.

Boys = 1/3(600)

Boys = 200

For finding number of girls:

Girls = total - boys

Girls = 600 - 200

Girls = 400

i hope it will help you!

8 0

4 years ago

Read 2 more answers

a grocery store sells and imported specialty cheesecake for $11 and its own store baked cheesecake for five Use the distributive

Radda [10]

I think its 17 the answer

7 0

3 years ago

10 burgers cost$600 what is the cost of 1 burger

Alisiya [41]

Answer:

1 burger would cost $60

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

The coordinates of quadrilateral PQRS are P(–3, 0), Q(0, 4), R(4, 1), and S(1, –3). What best describes the quadrilateral?

denis-greek [22]

Answer:

Square

Step-by-step explanation:

Plot the vertices of the quadrilateral PQRS on the coordinate plane (see attached diagram). The diagram shows that this is a square. Let's prove it.

1. Find all sides lengths:

$PQ=\sqrt{(-3-0)^2+(0-4)^2}=\sqrt{(-3)^2+(-4)^2}=\sqrt{9+16}=\sqrt{25}=5\\ \\QR=\sqrt{(0-4)^2+(4-1)^2}=\sqrt{(-4)^2+(3)^2}=\sqrt{16+9}=\sqrt{25}=5\\ \\RS=\sqrt{(4-1)^2+(1-(-3))^2}=\sqrt{(3)^2+(4)^2}=\sqrt{9+16}=\sqrt{25}=5\\ \\SP=\sqrt{(1-(-3))^2+(-3-0)^2}=\sqrt{(4)^2+(-3)^2}=\sqrt{16+9}=\sqrt{25}=5$

All sides have the same lengths.

2. Find the slopes of all lines:

$PQ:\ \dfrac{4-0}{0-(-3)}=\dfrac{4}{3}\\ \\QR:\ \dfrac{1-4}{4-0}=-\dfrac{3}{4}\\ \\RS:\ \dfrac{-3-1}{1-4}=\dfrac{4}{3}\\ \\SP:\ \dfrac{0-(-3)}{-3-1}=-\dfrac{3}{4}$

Since the slopes of PQ and RS are the same, lines PQ and RS are parallel. Since the slopes of QR and SP are the same, lines QR and SP are parallel.

The slopes $\frac{4}{3}$ and $-\frac{3}{4}$ have the product of

$-\dfrac{3}{4}\cdot \dfrac{4}{3}=-1,$

then lines are pairwise perpendicular.

This means PQRS is a square.

4 0

4 years ago

You might need: CalculatorThe angle O, is located in Quadrant III, and sin((.)1213What is the value of cos((,)?Express your answ

Wewaii [24]

We know that:

$\sin (\theta_1)=-\frac{12}{13}$

There is also an interesting property that relates the sine and the cosine of an angle:

$\sin ^2(\theta_1)+\cos ^2(\theta_1)=1$

We can find the cosine of theta using this equation:

$\begin{gathered} \cos ^2(\theta_1)=1-\sin ^2(\theta_1) \\ \cos (\theta_1)=\sqrt{1-\sin^2(\theta_1)} \\ \cos (\theta_1)=\sqrt[]{1-(-\frac{12}{13})^2} \\ \lvert\cos (\theta_1)\rvert=\sqrt[]{1-\frac{144}{169}}=\sqrt[]{\frac{25}{169}} \\ \lvert\cos (\theta_1)\rvert=\frac{5}{13} \end{gathered}$

Since theta is in the third quadrant then its cosine must be a negative number so:

$\cos (\theta_1)=-\frac{5}{13}$

3 0

1 year ago