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3 years ago

QUESTION 9 Convert 0.85 decimal to a fraction (do not reduce)

Mathematics

1 answer:

snow_tiger [21]3 years ago

8 0

Answer:

85/100

Step-by-step explanation:

0.85 from a decimal is equal to 85/100 in fractions

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Larissa is considering two summer jobs. A job at the mall pays $400 per week plus $15 for every hour of overtime. A job at the m

Rina8888 [55]

Solve using system of equations!
Let y=total amount of money and x=hours of overtime.
mall: y=400+15x
movies: y=360+20x
Solve! Set the equations equal to each other to find x.
400+15x=360+20x
40=5x
x=8
After 8 hours of overtime the movies would pay her more.

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3 years ago

A family decides to put tiles in the entryway of their home. The entryway has an area of 7 square meters. If each tile is 5 cent

lyudmila [28]

9514 1404 393

Answer:

2800 tiles

Step-by-step explanation:

Each tile has an area of (0.05 m)² = 0.0025 m². Then the number of tiles required to cover 7 square meters is ...

(7 m²)/(0.0025 m²/tile) = 2800 tiles

It will take 2800 tiles to cover the entryway.

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3 years ago

A recent study found that the average length of caterpillars was 2.8 centimeters with a

pogonyaev

Using the normal distribution, it is found that there is a 0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

In this problem, the mean and the standard deviation are given, respectively, by:

$\mu = 2.8, \sigma = 0.7$ .

The probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters is <u>one subtracted by the p-value of Z when X = 4</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{4 - 2.8}{0.7}$

Z = 1.71

Z = 1.71 has a p-value of 0.9564.

1 - 0.9564 = 0.0436.

0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.

More can be learned about the normal distribution at brainly.com/question/24663213

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2 years ago

The lengths of two sides of a right triangle are 12 inches and 15 inches. What is the difference between the two possible length

Anit [1.1K]

I get 10.2 for this answer

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3 years ago

Look at the picture of a scaffold used to support construction workers. The height of the scaffold can be changed by adjusting t

maria [59]

Using the Pythagorean on the right triangle PQR, with PQ and QR as the legs and PR as the hypotenuse,

$14^2 +6^2 =(PR)^2\\\\(PR)=\sqrt{14^2 +6^2}\\\\PR \approx \boxed{15.23 \text{ ft}}$

$(QR)^2 +6^2 =16^2\\\\(QR)^2 =16^2 -6^2\\\\QR=\sqrt{16^2 -6^2}\\\\QR \approx \boxed{14.83 \text{ ft}}$

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1 year ago