Answer:
347 is the initial spider population
Step-by-step explanation:
y = ab^x
is the formula for exponential growth and decay
a = the initial value
b is the growth or decay rate
b>1 it is the growth rate (b-1) is the percent
0<b<1 it is the decay rate (1-b) is the percent
y = 347(1.2)^x
347 is the initial spider population
(1.2-1) = .2 = 20 % growth rate
The first thing you must do is to calculate the weight of the gravel (w) that the truck holds (7.5 yards³). So, you have:
If the weight of 1 yard³ is 1.48 tons, then the weight of 7.5 yards³ is:
w=7.5x1.48 tons
w=11.1 tons
The problem says that the gravel will be placed in containers that each hold 3.7 tons of gravel,so, If they need 1 cotainer to place 3.7 tons, how many containers they need to place 11.1 tons?
1 container-------3.7 tons of gravel
x-------11.1 tons of gravel
x=(11.1x1)/3.7
x=11.1/3.7
x=3 containers
H<span>ow many containers of this size are needed to hold all the gravel from one truck?
</span>
The answer is: 3 containers.
Answer: 85.5
Step-by-step explanation:
There are 22 data points in the data set.
We can find the median by looking at the 11th and 12th scores, and averaging them.
The 11th score is 85
The 12th score is 86
The average of the two is 85.5
Hence the answer is 85.5
<span>√9/49
First you figure out the square root of 9 which is 3 since 3 x 3 equals 9. Then you find the square root of 49 which is 7 since 7 x 7 equals 49. Therefore, the answer is 3/7</span>
<h2>2 units down</h2><h2>1 unit to the left</h2>