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timofeeve [1]
3 years ago
11

Can somebody please help me? I don't understand this!

Mathematics
1 answer:
Xelga [282]3 years ago
5 0
Use the base of the triangle as the diameter, which in this case is 16, divide it by 2, which is 8, and then square it, which is 64, and multiply by Pi (64 times Pi is 200.96) so you can find the area of the whole circle which is 200.96ft^2. Since this is an equilateral triangle, the height might be 16, so using the area of a triangle, A=BH times 1/2, We multiply 16 by 16 which is 256. 256 times 1/2 is 128. So the area of the triangle will be 128ft^2. We then subtract our areas, 200.96-128 which is 72.96. Then therefore the area of the circle will be 72.96ft^2. I may be wrong, but this is what I think.
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Read 2 more answers
Write an equation for the line parallel to the given line that contains C. <br> C (1,8); 5/7x + 7
Genrish500 [490]

-------------------------------------------------------------------------------------------------------------

Answer:  \textsf{y = 5/7x + 51/7}

-------------------------------------------------------------------------------------------------------------

Given: \textsf{Goes through (1, 8) and is parallel to y = 5/7x + 7}

Find:  \textsf{Write an equation that follows that criteria}

Solution: We know that our equation is going to parallel to the line that was given therefore the slope would stay the same at 5/7.  We also have a point so we can plug in the values into the point-slope form, distribute, and solve for y.

<u>Plug in the values</u>

  • \textsf{y - y}_1\textsf{ = m(x - x}_1\textsf{)}
  • \textsf{y - 8 = 5/7(x - 1)}

<u>Distribute</u>

  • \textsf{y - 8 = (5/7 * x) + (5/7 * (-1))}
  • \textsf{y - 8 = 5/7x - 5/7}

<u>Add 8 to both sides</u>

  • \textsf{y - 8 + 8 = 5/7x - 5/7 + 8}
  • \textsf{y = 5/7x - 5/7 + 8}
  • \textsf{y = 5/7x + 51/7}

Therefore, the final equation that follows the description that was provided in the problem statement is y = 5/7x + 51/7.

4 0
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