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3 years ago

What is one million divided by 32???????

Mathematics

2 answers:

Fiesta28 [93]3 years ago

7 0

One million / 32 =thirty-one thousand two hundred fifty

Hope this helps!!!! :D

Zielflug [23.3K]3 years ago

3 0

31520 is the answer for 1000000/32

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Solve for d. | - 2d|<10

Romashka-Z-Leto [24]

Your question: Find D in | - 2d|<10

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SOLVING....

Solve the absolute value

|−2d| < 10

−2d < 10

−2d > −10

Solve −2d < 10 for D

Divide each side by -2

-2d ÷ -2 < 10 ÷ -2

d > -5

Now Solve −2d > −10

Divide each side by -2

-2d ÷ -2 > -10 ÷ -2

d < 5

So D is d < 5 and d > -5

7 0

3 years ago

10. The length of the radius of a bicycle wheel is 14 inches. Which of the following is closest to the circumference of the whee

Elina [12.6K]

Answer:

87.92

Step-by-step explanation:

you have your radius 14 inches to get the answer is

1: pie is 3.14

2: circumference is 2× 3.14×14

3: 3.14×14

4: 43.96 × 2

5 0

3 years ago

I need help :,)

Dmitry_Shevchenko [17]

Answer:

add 17.50 to 8.75 you get 26.25

7 0

2 years ago

Read 2 more answers

Two lighthouses are located 75 miles from one another on a north-south line. If a boat is spotted S 40o E from the northern ligh

yuradex [85]

Answer:

The northern lighthouse is approximately $24.4\; \rm mi$ closer to the boat than the southern lighthouse.

Step-by-step explanation:

Refer to the diagram attached. Denote the northern lighthouse as $\rm N$ , the southern lighthouse as $\rm S$ , and the boat as $\rm B$ . These three points would form a triangle.

It is given that two of the angles of this triangle measure $40^{\circ}$ (northern lighthouse, $\angle {\rm N}$ ) and $21^{\circ}$ (southern lighthouse $\angle {\rm S}$ ), respectively. The three angles of any triangle add up to $180^{\circ}$ . Therefore, the third angle of this triangle would measure $180^{\circ} - (40^{\circ} + 21^{\circ}) = 119^{\circ}$ (boat $\angle {\rm B}$ .)

It is also given that the length between the two lighthouses (length of $\rm NS$ ) is $75\; \rm mi$ .

By the law of sine, the length of a side in a given triangle would be proportional to the angle opposite to that side. For example, in the triangle in this question, $\angle {\rm B}$ is opposite to side $\rm NS$ , whereas $\angle {\rm S}$ is opposite to side ${\rm NB}$ . Therefore:

$\begin{aligned} \frac{\text{length of NS}}{\sin(\angle {\rm B})} = \frac{\text{length of NB}}{\sin(\angle {\rm S})} \end{aligned}$ .

Substitute in the known measurements:

$\begin{aligned} \frac{75\; \rm mi}{\sin(119^{\circ})} = \frac{\text{length of NB}}{\sin(21^{\circ})} \end{aligned}$ .

Rearrange and solve for the length of $\rm NB$ :

$\begin{aligned} & \text{length of NB} \\ =\; & (75\; \rm mi) \times \frac{\sin(21^{\circ})}{\sin(119^{\circ})} \\ \approx\; & 30.73\; \rm mi\end{aligned}$ .

(Round to at least one more decimal places than the values in the choices.)

Likewise, with $\angle {\rm N}$ is opposite to side ${\rm SB}$ , the following would also hold:

$\begin{aligned} \frac{\text{length of NS}}{\sin(\angle {\rm B})} = \frac{\text{length of SB}}{\sin(\angle {\rm N})} \end{aligned}$ .

$\begin{aligned} \frac{75\; \rm mi}{\sin(119^{\circ})} = \frac{\text{length of SB}}{\sin(40^{\circ})} \end{aligned}$ .

$\begin{aligned} & \text{length of SB} \\ =\; & (75\; \rm mi) \times \frac{\sin(40^{\circ})}{\sin(119^{\circ})} \\ \approx\; & 55.12\; \rm mi\end{aligned}$ .

In other words, the distance between the northern lighthouse and the boat is approximately $30.73\; \rm mi$ , whereas the distance between the southern lighthouse and the boat is approximately $55.12\; \rm mi$ . Hence the conclusion.

4 0

3 years ago

HELP ME ASAP PLEASE?!?!

miss Akunina [59]

A True

Congruent means to have the same shape and size or when we can cut them out and then match them up completely.

3 0

3 years ago

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