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KonstantinChe [14]
3 years ago
10

How to solve 4x + 10= -26

Mathematics
2 answers:
My name is Ann [436]3 years ago
6 0
Subtract 10 from both sides
4x = -26 -10
simplify
4x = -36
divide both sides by 4
x = -36/4
x = -9
hope this helps!
Damm [24]3 years ago
3 0
As so

4x+10=-26
-10 -10

4x/4=-36/4

x=-9
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According to the table, what was the hiker’s total displacement?
shtirl [24]

Answer:

A: 0

Step-by-step explanation:

Important to remember - total displacement is the direct distance between the start and finish points, and isn't always equal to the total distance travelled.

In the case of the table above, the hiker travels the same distance in opposite directions, which actually means they cancel each other out! Traveling 4 km to the west, then 4 km to east means you end up in the same spot, right? So your total displacement is 0! (or 4 - 4, which equals 0). Same happens with the north-south hikes - the hiker ends up in the same spot, as the displacement is equal to 6 - 6 = 0.

So, the total displacement of the hiker is 0. (Even though the hiker travelled 20 km!)

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2 years ago
Let A = any rational number is the absolute value of a different if A is a positive number or negative number Explain
artcher [175]

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5 0
3 years ago
9 time as many as 5 is 45
Nonamiya [84]
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Read 2 more answers
A batch of 40 semiconductor chips is inspected by choosing a sample of 5 chips. Assume 10 of the chips do not conform to custome
butalik [34]

Answer:

a) 658008 samples

b) 274050 samples

c) 515502 samples

Step-by-step explanation:

a) How many ways sample of 5 each can be selected from 40 is just a combination problem since the order of selection isn't important.

So, the number of samples = ⁴⁰C₅ = 658008 samples

b) How many samples of 5 contain exactly one nonconforming chip?

There are 10 nonconforming chips in the batch, and 1 nonconforming chip for the sample of 5 be picked from ten in the following number of ways

¹⁰C₁ = 10 ways

then the remaining 4 conforming chips in a sample of 5 can be picked from the remaining 30 total conforming chips in the following number of ways

³⁰C₄ = 27405 ways

So, total number of samples containing exactly 1 nonconforming chip in a sample of 5 = 10 × 27405 = 274050 samples

c) How many samples of 5 contain at least one nonconforming chip?

The number of samples of 5 that contain at least one nonconforming chip = (Total number of samples) - (Number of samples with no nonconforming chip in them)

Number of samples with no nonconforming chip in them = ³⁰C₅ = 142506 samples

Total number of samples = 658008

The number of samples of 5 that contain at least one nonconforming chip = 658008 - 142506 = 515502 samples

6 0
3 years ago
Jonathan deposited $20 in a savings account earning 5% interest, compounded annually.
Semenov [28]

Answer:

12$

Step-by-step explanation:

3 0
3 years ago
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