Um, we see that the slice created the triangle, and the formula to find the area of the triangle:
1/2×B×h where B represent Base and h represent height.
In this case, Base=5 cm
Height=11 cm
A=1/2×11×5
A=5.5×5
A=27.5 square cm. As a result, the area of the resulting two-dimensional cross section is 27.5 square cm. Hope it help!
It’s written in slope intercept form .
Answer:
99 points
Step-by-step explanation:
Average of a data a is the sum of the data divided by the number of data.
Average = sum of data ÷ number of data
A = T/n .....1
For the average of 5 test to be 90.
The total sum of score must be;
Number of tests n = 5
Average A = 90
Substituting into equation 1
90 = T/5
T = 90×5 = 450 points
The total score must be equal to 450 point to have an average of 90 points
The sum of the first four test is;
88+84+88+91 = 351
Let x represent the first score,
351 + x = 450
x = 450 - 351
x = 99 points
The minimum score she can get in the fifth test is 99 points
Answer:
(4/2 × 2/2 × 3/2) in.³ =3 in.³
Step-by-step explanation:
Given :
C, D, and E are col-linear, CE = 15.8 centimetres, and DE= 3.5 centimetres.
To Find :
Two possible lengths for CD.
Solution :
Their are two cases :
1)
When D is in between C and E .
. . .
C D E
Here, CD = CE - DE
CD = 15.8 - 3.5 cm
CD = 12.3 cm
2)
When E is in between D and C.
. . .
D E C
Here, CD = CE + DE
CD = 15.8 + 3.5 cm
CD = 19.3 cm
Hence, this is the required solution.
