A = amount invested at 4%.

b = amount invested at 9%.

we know the total amount invested was $26500, thus a + b = 26500.

whatever% of anything is just (whatever/100) * anything.

how much is 4% of a? well, is just (4/100) * a, or 0.04a.

how much is 9% of b? well, is just (9/100) * b, or 0.09b.

we know the interest yielded for both amounts adds up to $1510, thus 0.04a + 0.09b = 1510.

$\bf \begin{cases}
a+b=26500\implies \boxed{b}=26500-a\\
0.04a+0.09b=1510\\
----------------\\
0.04a+0.09\left( \boxed{26500-a} \right)=1510
\end{cases}
\\\\\\
0.04-0.09a+2385=1510\implies -0.05a=-875
\\\\\\
a=\cfrac{-875}{-0.05}\implies a=17500$

how much was invested at 9%? well, b = 26500 - a.

7 0

3 years ago

Samantha’s college runs on a trimester schedule so she receives a bill 3 times a year for tuition. Each trimester costs $1,450,

matrenka [14]

3 times a year for 2 years is equal to 3 x 2, or 6. So we know that she will have to pay her bill 6 times.

The cost for each trimester is $1450, but we still have to add the book costs ($350). So, 1450 + 350 = 1800.

Now we know that she has to pay $1800 six times. So the equation will be:

1800 x 6 = 10800.

It will cost Samantha $10,800 to get her degree.

8 0

3 years ago

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