Given the quadratic function y=(3x−2)(x+4), what are the x-intercepts?
1 answer:
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9514 1404 393
Answer:
48 ft
Step-by-step explanation:
For the quadratic ax^2 +bx +c, the axis of symmetry is x = -b/(2a). For the given quadratic, which defines a parabola opening downward, the axis of symmetry defines the time at which the maximum height is reached.
t = -48/(2(-16)) = 1.5
Then the maximum height is ...
f(1.5) = (-16·1.5 +48)1.5 +12 = (24·1.5) +12
f(1.5) = 48
The maximum height the object will reach is 48 feet.
