solve 6/x -4 = 4/x for x and determine if the solution is extraneous or not. x = −8, extraneous x = −8, non-extraneous x = 8, ex

Question

zhenek [66]

3 years ago

11

solve 6/x -4 = 4/x for x and determine if the solution is extraneous or not. x = −8, extraneous x = −8, non-extraneous x = 8, ex

traneous x = 8, non-extraneous

Mathematics

1 answer:

disa [49] · Answer 1 · 2022-08-21T22:50:08+03:00

disa [49]3 years ago

5 0

$\frac{6}{x-4} = \frac{4}{x} \\ 6x=4(x-4)=4x-16 \\ 2x=-16 \\ x=-8$
To check: 6/(-8-4) = 4/-8
6/-12 = 4/-8
1/-2 = 1/-2
Therefore, <span>x = −8, non-extraneous</span>