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olganol [36]
4 years ago
8

a bakery can make 175 pasteries a day. the bakery has been sold out for 3 days in a row. Determine if an estimate or exact amoun

t is needed. then determine how many pasteries were sold during the 3 days.
Mathematics
2 answers:
AleksandrR [38]4 years ago
7 0
An exact amount of 525 pastries because the bakery can only make a maximum of 175 daily so there would be no estimate since you have the exact number.
kumpel [21]4 years ago
3 0
525 pastries were sold in 3 days.
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Find the slope of the line passing through the points (-4, 0) and (7, 0). please help!!:)
guapka [62]

The slope of the line passing through the points (-4 , 0) and (7 , 0) is 0 ⇒ 3rd answer

Step-by-step explanation:

The formula of the slope of a line is m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

where (x_{1},y_{1})  and  (x_{2},y_{2}) are two points on the line

To find the slope

  • Let one of the two points to be (x_{1},y_{1})
  • Let the other point (x_{2},y_{2})
  • Substitute them in the formula of the slope
  • Calculate the value of m

∵ The line passes through points (-4 , 0) and (7 , 0)

∴ x_{1} = -4 and x_{2} = 7

∴ y_{1} = 0 and y_{2} = 0

- Substitute these values in the formula above

∴ m=\frac{0-0}{7--4}=\frac{0}{11}

∴ m = 0

The slope of the line passing through the points (-4 , 0) and (7 , 0) is 0

Learn more:

You can learn more about the slope of a line in brainly.com/question/2654504

#LearnwithBrainly

4 0
3 years ago
You can exchange 25 U.S. Dollars for 20 Euros. What is the exchange rate in U.S.
Mariulka [41]

Answer:

1.25 US Dollars per Euro

Step-by-step explanation:

25 USD = €20

Divide both sides by 20 and you get

1.25 USD = €1

4 0
4 years ago
Read 2 more answers
What is 4/7 of 70 apples
AlladinOne [14]

Answer:

40 apples

Step-by-step explanation:

4/7 of 70

1. rewrite in mathematical terms

4/7 * 70

2. solve

4/7 * 70

= 40

8 0
3 years ago
I really need help
telo118 [61]

Question 1:

(attached is a graph of the data)

The graph seems to show a negative trend. Each value is usually less than the value before it.

People may only want to see the first game and decide to not show up to any others. Or maybe, as more games occurred, the weather was colder and people didn't want to go out in the cold.

Question 2:

  • St John's    | 174000 | 173000
  • Sudbury     | 165000 | 155000
  • Saint John | 126000 | 123000
  • Chicoutimi | 160000 | 155000
  • Thun. bay  | 127000 | 122000
  • Regina       | 194000 | 193000
  • Trois-Riv.   | 140000 | 138000

(attached is a graph of the data)

I chose this graph type to demonstrate each city, as well as the change in population over time.

I notice that, for each city, the population decreased slightly from 1996 to 2001.

The graph shows the trend because the pink bar (2001) is lower than the orange bar (1996).

Predicting values for 2006:

  • St John's    | 172000
  • Sudbury     | 145000
  • Saint John | 120000
  • Chicoutimi | 150000
  • Thun. bay  | 117000
  • Regina       | 192000
  • Trois-Riv.   | 136000

To find these values, I found the difference from 1996 to 2001 (<em>for St John's: </em>174000-173000 = 1000). Since 1996 to 2001 is 5 years, and 2001 to 2006 is also 5 years, I can subtract 1000 from 2001's value (173000 - 1000 = 172000). Another example (for Saint John): 126000 - 123000 = 3000. 123000 - 3000 = 120000.

5 0
3 years ago
Everyone wants to watch football games on Thanksgiving. There are 3 games on in afternoon and 3 on at night. How many different
Vikki [24]

Answer:

Step-by-step explanation:

At afternoon there are 3 games, lets call them A1, A2, and A3. These are simultaneous, which means you can ONLY watch one of them.

At night there are other three, lets call them N1, N2 and N3. Which again, are simultaneous, so you need to chose only one.

So, you can, at most, watch 2 games: one in the afternoon (extracted from the set {A1, A2, A3}) and one at night (extracted from the set {N1, N2, N3}).

So, here what you need is ALL the possible combinations between afternoon and games. As thee choices are independent, this is, the game chosen at afternoon has no effect on the night decision, we can just multiply the number of options in every set: 3*3 = 9. So there are 9 different combinations, which are:

A1 N1, A1 N2, A1 N3, A2 N1, A2 N2, A2 N3, A3 N1, A3 N2, A3 N3.

Here I supposed you watch a game in both, night and afternoon. If you can choose to NOT watch any game, the sets will have 4 elements but the reasoning is equal.  

7 0
3 years ago
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