Ask question

Ask question

All categories

3 years ago

8

a bakery can make 175 pasteries a day. the bakery has been sold out for 3 days in a row. Determine if an estimate or exact amoun

t is needed. then determine how many pasteries were sold during the 3 days.

2 answers:

AleksandrR [38]3 years ago

7 0

An exact amount of 525 pastries because the bakery can only make a maximum of 175 daily so there would be no estimate since you have the exact number.

kumpel [21]3 years ago

3 0

525 pastries were sold in 3 days.

You might be interested in

Find the measure of the angle indicated by 19x+5.

Ugo [173]

Answer:

100

Step-by-step explanation:

16x + 19x + 5 = 180 {co-interior angles are supplementary}

Combine like terms;

35x + 5 = 180

Subtract 5 from both sides

35x = 180 - 5

35x = 175

Divide both sides by 35

x = 175/35

x = 5

19x + 5 = 19*5 + 5

= 95 + 5

= 100

3 0

3 years ago

Read 2 more answers

A square pyramid is sliced in half, parallel to the base.

DIA [1.3K]

Answer:

I think the answer is a because it not getting any smaller

7 0

2 years ago

Read 2 more answers

How do I find slope?

Korolek [52]

To find the slope in the graph you need to find two perfect points on the line then count how many times you went up which is the y over how many times you go right which is the x its called the rise/run. To find the slope in the equation use the formula y2-y1/x2-x1.

7 0

3 years ago

Read 2 more answers

The average cost to own and operate a car in the United States for 2020 was $0.524 per mile.

sp2606 [1]

Answer:

y = 0.524m + b is the answerrrr

3 0

2 years ago

Three forces act on an object. Two of the forces are at an angle of 95◦ to each other and have magnitudes 35 N and 7 N. The thir

Cerrena [4.2K]

We want to find $\vec F_4$ such that the object needs is in equilibrium:

$\vec F_1+\vec F_2+\vec F_3+\vec F_4=\vec0$

We're told that $F_1=35\,\mathrm N$ , $F_2=7\,\mathrm N$ , and $F_3=9\,\mathrm N$ . We also know the angle between $\vec F_1$ and $\vec F_2$ is 95º, which means

$\vec F_1\cdot\vec F_2=F_1F_2\cos95^\circ=245\cos95^\circ$

$\vec F_3$ is perpendicular to both $\vec F_1$ and $\vec F_2$ , so $\vec F_1\cdot\vec F_3=\vec F_2\cdot\vec F_3=0$ .

If we take the dot product of $\vec F_1$ with the sum of all four vectors, we get

$\vec F_1\cdot(\vec F_1+\vec F_2+\vec F_3+\vec F_4)=0$

$\vec F_1\cdot\vec F_1+\vec F_1\cdot\vec F_2+\vec F_1\cdot\vec F_3+\vec F_1\cdot\vec F_4=0$

${F_1}^2+\vec F_1\cdot\vec F_2+0+\vec F_1\cdot\vec F_4=0$

$\implies\vec F_1\cdot\vec F_4=-\left({F_1}^2+\vec F_1\cdot\vec F_2\right)$

We can do the same thing with $\vec F_2$ and $\vec F_3$ :

$\vec F_2\cdot(\vec F_1+\vec F_2+\vec F_3+\vec F_4)=0$

$\implies\vec F_2\cdot\vec F_4=-\left(\vec F_1\cdot\vec F_2+{F_2}^2\right)$

$\vec F_3\cdot(\vec F_1+\vec F_2+\vec F_3+\vec F_4)=0$

$\implies\vec F_3\cdot\vec F_4=-{F_3}^2$

Finally, if we do this with $\vec F_4$ , we get

$\vec F_4\cdot(\vec F_1+\vec F_2+\vec F_3+\vec F_4)=0$

$\implies{F_4}^2=-\left(\vec F_1\cdot\vec F_4+\vec F_2\cdot\vec F_4+\vec F_3\cdot\vec F_4\right)$

$\implies{F_4}^2=-\left(-\left({F_1}^2+\vec F_1\cdot\vec F_2\right)-\left(\vec F_1\cdot\vec F_2+{F_2}^2\right)-{F_3}^2\right)$

$\implies F_4=\sqrt{{F_1}^2+{F_2}^2+{F_3}^2+2(\vec F_1\cdot\vec F_2)}$

$\implies\boxed{F_4\approx36.2\,\mathrm N}$

7 0

3 years ago