The first-serve percentage of a
tennis player in a match is normally distributed with a standard deviation of
4.3%. If a sample of 15 random matches of
the player is taken, the mean
first-serve percentage is found to be 26.4%. The margin of error of the sample
mean is 83.71%.
The first one (2-x^3) is the correct one
Answer:
I put all the steps down. I don't know which one you want. I hope you understand it now.
Step-by-step explanation:
b = baking time
p = preperation time
p = 1/3b
12 = 1/3b
b = 12*3
b = 36 minutes
<span>If two numbers on a graph differ by 1, without scale, the amount of inequality could vary infinitely. If the scale is 2, a difference of 1 is half the scale amount, but if the scale is 1000, the difference may be negligible. It is the scale that shows the degree to which the entries differ.</span>
<span>5/8 divided 2
(5/8) / 2 = 5/8 * 1/2 = 5/16
Hope it helps</span>
