0.05 kilogramos.................
Answer:
<h2>1.84feet</h2>
Step-by-step explanation:
Using the formula for finding range in projectile, Since range is the distance covered in the horizontal direction;
Range 
U is the velocity of the arrow
H is the maximum height reached = distance below the bullseye reached by the arrow.
R is the horizontal distance covered i.e the distance of the target from the archer.
g is the acceleration due to gravity.
Given R = 60ft, U = 250ft/s, g = 32ft/s H = ?
On substitution,
Squaring both sides we have;
The arrow will hit the target 1.84feet below the bullseye.
The answer is D. -15 because I am assuming that the vertical lines mean brackets, and we have to work out the brackets first (according to BIDMAS). Doing so, -6 + 2 = -4 and -4 + -11 = -15.
Answer:
b 24/25
Step-by-step explanation:
SOHCAHTOA
tan is Opposite over Adjacent sides of the triangle from the perspective of angle A
so the opposite side was 24 and the adjacent side was 25
so the answer is 24/25 aka B
<span>It is possible to have an obtuse triangle that also contains a 35° angle.
Yes, this is true.
That's because an obtuse angle just means it's more than 90 but less than 180 degrees.
</span><span>It is possible to have a right triangle that also contains a 110° angle.
</span>No, this is false.
That's because a right triangle already has 90. That means that the two remaining angles must add up to 90 and not more or less.
<span>It is possible to have an acute triangle that also contains a 70° angle.
Yes, this is true.
An acute triangle means that all of the angles are more than 0 but less than 90.
Hope this helps :)</span>
