Answer:
The sample size required is, <em>n</em> = 502.
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for population proportion is:

The margin of error is:

Assume that 50% of the people would support this political candidate.
The margin of error is, MOE = 0.05.
The critical value of <em>z</em> for 97.5% confidence level is:
<em>z</em> = 2.24
Compute the sample size as follows:

![n=[\frac{z_{\alpha/2}\times \sqrt{\hat p(1-\hat p)}}{MOE}]^{2}](https://tex.z-dn.net/?f=n%3D%5B%5Cfrac%7Bz_%7B%5Calpha%2F2%7D%5Ctimes%20%5Csqrt%7B%5Chat%20p%281-%5Chat%20p%29%7D%7D%7BMOE%7D%5D%5E%7B2%7D)
![=[\frac{2.24\times \sqrt{0.50(1-0.50)}}{0.05}]^{2}\\\\=501.76\\\\\approx 502](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B2.24%5Ctimes%20%5Csqrt%7B0.50%281-0.50%29%7D%7D%7B0.05%7D%5D%5E%7B2%7D%5C%5C%5C%5C%3D501.76%5C%5C%5C%5C%5Capprox%20502)
Thus, the sample size required is, <em>n</em> = 502.
2. Tuesday
3.1/7 and 0.14
4. neither likely or unlikely because most days occur 52 times through out the year.
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We have been given an equation of hyperbola
. We are asked to find the center of hyperbola.
We know that standard equation of a vertical hyperbola is in form
, where point (h,k) represents center of hyperbola.
Upon comparing our given equation with standard vertical hyperbola, we can see that the value of h is 6.
To find the value of k, we need to rewrite our equation as:

Now we can see that value of k is
. Therefore, the vertex of given hyperbola will be at point
and option D is the correct choice.
The garden area is maximum when the enclosure is a square.
If a is the length of the side of the square then the length of the building is also a.
The perimeter length is 4a made up of 81+a feet, so 81+a=4a and 3a=81 making a=27 feet.