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jonny [76]
3 years ago
13

An earthquake measuring 6.4 on the Richter scale struck Japan in July 2007, causing extensive damage. Earlier that year, a minor

earthquake measuring 3.1 on the Richter scale was felt in parts of Pennsylvania. How many times more intense was the Japanese earthquake than the Pennsylvania earthquake
Mathematics
1 answer:
a_sh-v [17]3 years ago
3 0

Answer:

10

Step-by-step explanation

The earthquake  measures 6.4 on the Richter scale which struck Japan in Jullu 2007 and caused and extensive damage. Earlier that year, a minor earthquake measuring 3.1 in the Richter scale has stroked in parts of Pennsylvania.

Fomular:

The magnitude of an earthquake is M log(I/S)

where I donates the intensity of the earthquake and S be the intensity of the standard earthquake.

Calculation:

Consider that M1 be the magnitude Japanese earthquake and M2 be the magnitude of the Pennsylvania earthquake and L1 be the intensity of the Japanese earthquake and L2 the intensity of the Pennsylvania  earthquake.

Here the magnitude of the Japanese earthquake is M1 = 6.14 and the magnitude of the Pennsylvania is M2 = 3.1

By the use of magnitude of the earthquake fomular M = log I1/S, the intensity of the Japanese earthquake is calculated as follows .

M1 = log I1/S

I1/s = 10

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