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Vesnalui [34]
4 years ago
13

Tue or FalseIn Euclidean geometry, a triangle can have, at most, two 90 degree angles

Mathematics
1 answer:
zmey [24]4 years ago
4 0

no it cannot.


and 90 degree angle is

l

l

l

l

__________________________


it cannnot

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erica [24]

Answer:

this is correct not sure what else to do with it

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3 years ago
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A square room has an area of 200 square feet. how long is each wall? show your work to explain why
wlad13 [49]

Answer:

about 14.142ft

Step-by-step explanation:

A square has four equal sides.

The area of a square:      length * width = area

Because you know that all of the sides are equal, you can just say:

length * length = area

Multiplying a value (in this case, length) by itself is the same thing as squaring it. So, you can simplify the equation further by writing:

length² = area

Fill in what you know:

length² = 200ft²

Now, work the problem backwards by taking the square root of 200 to find the length:

√length² = √200ft²

length = 14.142ft

So, each wall is 14.142ft long

You can test this by working the problem in reverse:

14.142ft * 14.142ft ≈ 200ft²

7 0
3 years ago
Hey can someone give me the answer to the problem
sladkih [1.3K]

a. The rocket splashes down after 63.94 seconds.

b. The rocket peaks at 7386.68 m

<h3>a. How to find when the rocket splashes down?</h3>

Since the height of the rocket is h(t) = -4.9t² + 370t + 402, the rocket splashes down when h(t) = 0.

So, h(t) = 0

-4.9t² + 370t + 402 = 0

Using the quadratic formula, we find t.

t = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}

where a = -4.9, b = 370 and c = 402

So, t = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}\\= \frac{-307 +/- \sqrt{(307)^{2} - 4(-4.9)(402)} }{2(-4.9)}\\= \frac{-307 +/- \sqrt{94249 + 7879.2} }{-9.8)}\\= \frac{-307 +/- \sqrt{102128.2} }{-9.8)}\\= \frac{-307 +/- 319.58}{-9.8)}\\= \frac{-307 + 319.58}{-9.8)} or \frac{-307 - 319.58}{-9.8)}\\= \frac{12.58}{-9.8)} or \frac{-626.58}{-9.8}\\= -1.28 or 63.94

Since t cannot be negative t = 63.94 s

So, the rocket splashes down after 63.94 seconds.

<h3>b. How to find the peak of the rocket?</h3>

Since h(t) = -4.9t² + 370t + 402, to find the time the rocket reaches it peak, we differentiate h(t) with respect to t and equate to zero.

Soi, dh(t)/dt = d(-4.9t² + 370t + 402)/dt

= -9.8t + 370

dh(t)/dt = 0

-9.8t + 370 = 0

-9.8t = -370

t = -370/-9.8

t = 37.76 s

Substitung t = 37.76 into h(t), we have

h(t) = -4.9t² + 370t + 402

h(37.76) = -4.9(37.76)² + 370(37.76) + 402

h(37.76) = -4.9(1425.82) + 370(37.76) + 402

h(37.76) = -6986.518 + 13971.2 + 402

h(37.76) = 7386.682 m

h(37.76) ≅ 7386.68 m

So, the rocket peaks at 7386.68 m

Learn more about height of a rocket here:

brainly.com/question/25865512

#SPJ1

7 0
2 years ago
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irakobra [83]
4 5/6 + 5 7/8 = 10 17/24
4 0
3 years ago
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