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Vesnalui [34]
4 years ago
13

Tue or FalseIn Euclidean geometry, a triangle can have, at most, two 90 degree angles

Mathematics
1 answer:
zmey [24]4 years ago
4 0

no it cannot.


and 90 degree angle is

l

l

l

l

__________________________


it cannnot

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Solve the equation: 1/6d+2/3=1/4(d-2)
nlexa [21]

d/6+2/3=1/4(d-2)

d/6+2/3=d-2/4

2d+8=3(d-2)

2d+8=3d-6

8=3d-6-2d

8=d-6

8+6=d

14=d

d=14



8 0
3 years ago
Please help
alexandr402 [8]
\bf 3\sqrt[3]{2a} -6\sqrt[3]{2a}\qquad \stackrel{add ing~like-terms}{\implies }\qquad -3\sqrt[3]{2a}
3 0
3 years ago
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Find the height of a square pyramid that has a volume of 75 cubic feet and a base length of 5 feet.
Rudiy27

Answer:

9 ft

Step-by-step explanation:

Let's begin with the formula for the volume of a square pyramid.  If s is the base length, then the area of the base is s^2.  The volume of the pyramid is then V = (1/3)(base area)(height).  We know the volume and the base length (s), and want to find the height.  Solving V = (1/3)(base area)(height)

for height, we get:

3V = (base area)(height), or

    3V

---------------- = height

base area

Substituting 75 ft^3 for V and (5 ft)^2 for base area, we get:

               3(75 ft^3)              9 ft

height = ------------------ = ----------------- = 9 ft

                 25 ft^2                   1

3 0
3 years ago
NEED HELP PLEASE WILL MARK BRAINLIEST !!!
Leona [35]
The answer you need is b
3 0
3 years ago
( simultaneous equations)
daser333 [38]

Answer:

See method below.

Step-by-step explanation:

m/n + n/3 = 2

2/m + n = 4    

First  eliminate the fractions by multiplying the first equation by 3n:-

3m + n^2 = 6n...........(1)

and the second equation by m:-

2 + mn = 4m..............(2)

Now we solve using substitution:-

From equation  (2):-

4m - mn = 2

m = 2 / (4 - n)

Now substitute for m in equation (1):-

6/ (4 - n) + n^2 = 6n

6 + n^2(4 - n) = 6n(4 - n)

6 + 4n^2 - n^3 = 24n - 6n^2

n^3 - 10n^2 + 24n - 6 = 0

This will not factor so we could solve this using graphical software.

To find the values of the variable m we substitute the found values of n into one of the original equations and solve for m.






6 0
4 years ago
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