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stepan [7]
2 years ago
6

Write the relation as a set of ordered pairs

Mathematics
1 answer:
Marina CMI [18]2 years ago
7 0

I don't know what the relation in your problem is, but I'll just explain this using my own example.

Let's use the following relation as the example (pretend it's a table of values):

x | y

0 |  1

2 |  4

4  |  7

6  | 10

To write the relation as ordered pairs, you need the x and y values from the table. An ordered pair is written like this: (x,y).

Based off of this explanation, the ordered pairs from this example would be:

(0,1) (2,4) (4,7) (6,10)

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Fill in the missing numbers<br>I need an answer ASAP<br><br>​
mamaluj [8]

Answer:

the missing numbers be 60 and 6 respectively

Step-by-step explanation:

The computation of the missing numbers are shown below:

Let us assume the missing numbers be x

a/

, \frac{1}{2} \times 30 =  \frac{1}{4} \times x\\\\15 =    \frac{1}{4} \times x\\\\x = 60

b.

\frac{1}{3} \times 12 =  \frac{2}{3} \times x\\\\4 =    \frac{2}{3} \times x\\\\x = 6

Hence, the missing numbers be 60 and 6 respectively

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3 years ago
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Answer:

5683.2 Euro's

Step-by-step explanation:

i=

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The total source voltage in the circuit is 6-3i V. What is the voltage at the middle source
Bezzdna [24]

Answer:

<em>The voltage at the middle source is</em> (2-4\mathbf{i})\ V

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<u>Voltage Sources in Series</u>

When two or more voltage sources are connected in series, the total voltage is the sum of the individual voltages of each source.

The figure shown has three voltage sources of values:

2 + 6\mathbf{i}

a + b\mathbf{i}

2 - 5\mathbf{i}

The sum of these voltages is:

V_t=4+a+(6+b-5)\mathbf{i}

Operating:

V_t=4+a+(1+b)\mathbf{i}

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4+a+(1+b)\mathbf{i}=6-3\mathbf{i}

Equating the real parts and the imaginary parts independently:

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Solving each equation:

a = 2

b = -4

The voltage at the middle source is (2-4\mathbf{i})\ V

5 0
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