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hram777 [196]
3 years ago
9

The height of the Empire State building is 1250 feet tall. Your friend ,who is 6 feet 3 inches tall, is standing nearby and cast

s a shadow that is 33 inches long. What is the length of the shadow of the Empire State building
Mathematics
1 answer:
IgorLugansk [536]3 years ago
8 0
75 inches / 33 inches : 1,250 / shadow

75 * shadow = 33 * 1,250

shadow = 41,250 / 75

shadow = 550 feet


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mojhsa [17]
Im not sure what you are asking for
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3 years ago
A gas is said to be compressed adiabatically if there is no gain or loss of heat. When such a gas is diatomic (has two atoms per
Tems11 [23]

Answer:

The pressure is changing at \frac{dP}{dt}=3.68

Step-by-step explanation:

Suppose we have two quantities, which are connected to each other and both changing with time. A related rate problem is a problem in which we know the rate of change of one of the quantities and want to find the rate of change of the other quantity.

We know that the volume is decreasing at the rate of \frac{dV}{dt}=-4 \:{\frac{cm^3}{min}} and we want to find at what rate is the pressure changing.

The equation that model this situation is

PV^{1.4}=k

Differentiate both sides with respect to time t.

\frac{d}{dt}(PV^{1.4})= \frac{d}{dt}k\\

The Product rule tells us how to differentiate expressions that are the product of two other, more basic, expressions:

\frac{d}{{dx}}\left( {f\left( x \right)g\left( x \right)} \right) = f\left( x \right)\frac{d}{{dx}}g\left( x \right) + \frac{d}{{dx}}f\left( x \right)g\left( x \right)

Apply this rule to our expression we get

V^{1.4}\cdot \frac{dP}{dt}+1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}=0

Solve for \frac{dP}{dt}

V^{1.4}\cdot \frac{dP}{dt}=-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}\\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}}{V^{1.4}} \\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}

when P = 23 kg/cm2, V = 35 cm3, and \frac{dV}{dt}=-4 \:{\frac{cm^3}{min}} this becomes

\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}\\\\\frac{dP}{dt}=\frac{-1.4\cdot 23 \cdot -4}{35}}\\\\\frac{dP}{dt}=3.68

The pressure is changing at \frac{dP}{dt}=3.68.

7 0
4 years ago
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mars1129 [50]

Answer:

They are on their simplified form.

Step-by-step explanation:

Since these numbers are prime numbers we can't simplify them. But we can change them to decimal.

1/2=0.5

1/3=0.3 (in which 3 repeats itself)

Hope this helps ;) ❤❤❤

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The length of JK rounded to the nearest hundredth is 4.72
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{x + y = 2
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1) I put them in two separate brakets.

2) I solved it by equating both of them.

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