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3 years ago

7

If Kawmae had 20 apple and gave Kim 2 how much apple would she have

1 answer:

tekilochka [14]3 years ago

6 0

She would have18 apples

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How does the 5 in the tens place<br> compare to the 5 in the ones place?<br> 3,055

morpeh [17]

Answer:

The 5 in the tens place has more value then the 5 in the ones place

Step-by-step explanation:

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3 years ago

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How many millimeters are there in 16 meters

Anika [276]

One of the very nice features of the metric system of measurements is that there is a set of standardized prefixes that can be applied to any of the units. Some of the more common ones are
.. micro- . . . one millionth
.. milli- . . . . one thousandth
.. centi- . . . .one hundredth
.. kilo- . . . . .one thousand

Thus, one millimeter is 1/1000 = 0.001 meter. There are 1000 of them in 1 meter, so
.. 16 m = 16000 mm

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3 years ago

1/2(6 2/3+1/4)-5/24=

Helen [10]

For this case we must simplify the following expression:

$\frac {1} {2} (6 \frac {2} {3} + \frac {1} {4}) - \frac {5} {24} =$

We convert the mixed number to an improper fraction:

$6 \frac {2} {3} = \frac {3 * 6 + 2} {3} = \frac {20} {3}$

So, by rewriting we have:

$\frac {1} {2} (\frac {20} {3} + \frac {1} {4}) - \frac {5} {24} =\\\frac {1} {2} (\frac {4 * 20 + 3 * 1} {4 * 3}) - \frac {5} {24} =\\\frac {1} {2} (\frac {80 + 3} {12}) - \frac {5} {24} =\\\frac {1} {2} (\frac {83} {12}) - \frac {5} {24} =$

$\frac {83} {24} - \frac {5} {24} =\\\frac {83-5} {24} =\\\frac {78} {24} =\\\frac {39} {12} =\\\frac {13} {4} =\\3 \frac {1} {4}$

Answer:

$3 \frac {1} {4}$

5 0

2 years ago

The length of the minute hand on a clock is 5in

GenaCL600 [577]

Answer:

25 Minutes

Step-by-step explanation:

Each minute sign represents 5 minutes gone by. When hand is on the 5, it is 25 minutes.

6 0

2 years ago

Can someone please help with NUMBER 7?!! It’s my last one I will mark brainliest to the best answer

Nikolay [14]

Answer:

1, 3, 9, 27

Step-by-step explanation:

$a_n = 3^{n - 1}$

You need the first 4 terms, so let n = 1, and evaluate the expression. Then do the same for n = 2, n = 3, and finally n = 4.

n = 1

$a_1 = 3^{1 - 1} = 3^0 = 1$

n = 2

$a_2 = 3^{2 - 1} = 3^1 = 3$

n = 3

$a_3 = 3^{3 - 1} = 3^2 = 9$

n = 4

$a_4 = 3^{4 - 1} = 3^3 = 27$

7 0

3 years ago