How many years are in 2/5 of a decade? Please answer soon this is due tomoroow
2 answers:
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Answer:
1) increasing on (-∞,-1] ∪ [1,∞), decreasing on [-1,0) ∪ (0,1]
is local maximum,
is local minimum
2) increasing on [1,∞), decreasing on (-∞,0) ∪ (0,1]
is absolute minimum
3) increasing on (-∞,0] ∪ [8,∞), decreasing on [0,4) ∪ (4,8]
is local maximum,
is local minimum
4) increasing on [2,∞), decreasing on (-∞,2]
is absolute minimum
5) increasing on the interval (0,4/9], decreasing on the interval [4/9,∞)
is local minimum,
is absolute maximum
Step-by-step explanation:
To find minima and maxima the of the function, we must take the derivative and equalize it to zero to find the roots.
1)
and
So, the roots are and
The function is increasing on the interval (-∞,-1] ∪ [1,∞)
The function is decreasing on the interval [-1,0) ∪ (0,1]
is local maximum,
is local minimum.
2)
and
So the root is
The function is increasing on the interval [1,∞)
The function is decreasing on the interval (-∞,0) ∪ (0,1]
is absolute minimum.
3)
and
So the roots are and
The function is increasing on the interval (-∞,0] ∪ [8,∞)
The function is decreasing on the interval [0,4) ∪ (4,8]
is local maximum,
is local minimum.
4)
has no solution and
is crtitical point.
The function is increasing on the interval [2,∞)
The function is decreasing on the interval (-∞,2]
is absolute minimum.
5) for
So the root is
The function is increasing on the interval (0,4/9]
The function is decreasing on the interval [4/9,∞)
is local minimum,
is absolute maximum.
Average reading score is given by the expression,
y = 0.153x + 255.4
Here, x in the number of years past 1970.
To find the year in which the average reading score is 259.378, substitute the value of 'y' in the given expression.
y = 0.153x + 255.4
259.378 = 0.153(x) + 255.4
0.153x = 259.378 - 255.4
0.153x = 3.978
x =
x = 26
That means given average reading score 259.378 will be 26 years after 1970.
Therefore, 1996 is the year in which the average reading score will be 259.378.
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