This shows that about 7 and 3 pounds of each chocolate were included in the mixture.
Let the number of pounds of both chocolates be x and y.
If Enrico sold a 10-pound box of assorted chocolates, hence;
x + y = 10 ................. 1
If some of the chocolates in the box sold for $1.75 per pound and some sold for $2.00 per pound with mixture sold for $1.90 per pound, then:
1.75x + 2x = 1.90 ................ 2
Solve equations 1 and 2 simultaneously.
x + y = 10 ................. 1 * 20
17.5x + 20x = 19 ................ 2 * 1
____________________________
20x + 20y = 200
17.5x + 20x = 19
Subtract
20x - 17.5x = 200 - 19
2.5x = 181x = 7.24
Substitute 7.24 into 1
x + y = 10
y = 10 - 7.24
x = 2.76
This shows that about 7 and 3 pounds of each chocolate were included in the mixture.
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Answer:
m <5=91 is the correct response to this question
Answer:
2/5
Step-by-step explanation:
0.4 = 4/10 which in simplest form is 2/5
Answer:
each dose = 6.7 mL ( to 1 decimal place)
Step-by-step explanation:
Total volume of vial = 20mL
each dose of vial = 1/3 of the total volume
let us express this fraction as a real number:
1/3 of 20 = 1/3 × 20
Since we are to express the answer as a decimal, let us convert the fraction to decimal:
1/3 = 0.3333
∴ 1/3 × 20 = 0.3333 × 20 = 6.667 mL
since we are dealing with drugs, it'll be appropraite to express the answer to 1 d.p
∴ each dose = 6.7 mL
Answer:
This system has no solutions.
Step-by-step explanation:
If we try to solve:
- 5x + 8 = 5x + 3
- 5x + 8 - 3 = 5x
- 5x + 5 = 5x
- 5x - 5x + 5 = 5x - 5x
- 5 = 0
Since there are no x values left over and the remaining solution is zero, there is no solution for this equation.
Hope this helps!!
