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Alborosie
2 years ago
7

, 5: Peter walks 5 m towards West, takes a right turn and walks 5m again. He then takes another right turn How far and walks 20m

. He then takes a Ònal right turn and walks 5m before stopping. How far is he from the starting point?

Mathematics
1 answer:
Molodets [167]2 years ago
5 0

In the figure, P is the starting point of Perter.

Q is the point of his first right turn which is 5m from the starting point.

R is the next point of his right turn which is again 5m from P.

T is another right turn which is 20m from R.

U is the stop point which is 5m from T.

It is clear that P is the starting point and U is the stop point.

We need to find PU.

From figure, PU = ST but ST = RT - RS and RS = QP

Therefore, PU = RT - QP

PU = 20 - 5 = 15m.

Hence, he is 15m far from the starting point.

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Answer:

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Step-by-step explanation:

Formatting the question gives;

a = mg - kv² / m

Make v subject of the formula as follows;

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(iii) Divide through by k

v² = (m²g - ma) / k

(iv) Take the square root of both sides

v = √ [(m²g - ma) / k]            --------------(ii)

From the question:

a = 2.8

m = 12

g = 9.8

k = 8/3

Substitute these values into equation (i) as follows;

v = √ [(12²(9.8) - 12(2.8)) / (8/3)]

v = √ [(1411.2 - 33.6) / (8/3)]

v = √ [1377.6 / (8/3)]

v = √ [1377.6 x (3/8)]

v = √ [1377.6 x 3 / 8)]

v = √ [516.6]

v = 22.73

v = 23 [to the nearest whole number]

Therefore v = 23 to the nearest whole number    

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