, 5: Peter walks 5 m towards West, takes a right turn and walks 5m again. He then takes another right turn How far and walks 20m
. He then takes a Ònal right turn and walks 5m before stopping. How far is he from the starting point?
1 answer:
In the figure, P is the starting point of Perter.
Q is the point of his first right turn which is 5m from the starting point.
R is the next point of his right turn which is again 5m from P.
T is another right turn which is 20m from R.
U is the stop point which is 5m from T.
It is clear that P is the starting point and U is the stop point.
We need to find PU.
From figure, PU = ST but ST = RT - RS and RS = QP
Therefore, PU = RT - QP
PU = 20 - 5 = 15m.
Hence, he is 15m far from the starting point.
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Simon is correct because even though the input values are opposite in the reflected function, any real number can be an input for an exponential growth function.
Verification of Choice
Let us consider the following exponential growth function.
y = Aeˣ ...........................(1)
This equation changes when it is reflected across the y axis and becomes,
y = Ae⁻ˣ ...........................(2)
Here, the set of all x values for which y is defined is known as the domain of this exponential growth function.
Therefore, the domain of exponential growth function 1 is the set of all real numbers, given by, x ∈ [-∞,∞]
The domain of function 2, which is a reflection of function 1, will also consist entirely of real numbers and will be given by x ∈ [-∞,∞ ]
Therefore, between Alissa and himself, Simon is right when he asserts that even if an exponential growth function is reflected across the y-axis, the domain will still consist only of real values.
Learn more on exponential growth function here:
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