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3 years ago

What is square root of 600 end root to the nearest tenth?

Mathematics

1 answer:

Triss [41]3 years ago

5 0

The square root of 600 is 24.49489742, so you round it to 24.5.

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The set of relative max/min and absolute max/min are referred to as _______.

PIT_PIT [208]

Answer:

Step-by-step explanation:

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3 years ago

Can someone please help me with my maths

Korvikt [17]

Answer:

Step-by-step explanation:

Recall that the "point-slope" form of a linear equation may be expressed as

y = mx + b,

where m is the gradient.

If m is negative, the gradient is negative.

If m is positive, the gradient is positive.

In our case, if we consider option A,

x + 3y = -2 (rearranging)

3y = -x -2

y = (-1/3) x - (2/3)

if we compare this to the general equation at the top, we can see that

gradient, = m = (-1/3) which is negative.

hence option a has a negative gradient.

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3 years ago

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Help Me Please I will give brainliest if correct!

il63 [147K]

Answer:

9 $c^{7}$

Step-by-step explanation:

$c^{-4}$ is equal to $\frac{1}{c^{4} }$ . $\frac{9c^{3} }{\frac{1}{c^{4} } }$ is equal to $9c^{7}$ .

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2 years ago

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Find the product of the complex numbers. Express your answer in trigonometric form.

Marianna [84]

In order to find the product of two complex numbers their magnitudes are multiplied and their arguments(measure of angles) are added up.

For z₁
Magnitude = 4
Argument = π/3

For z₂
Magnitude = 3
Argument = 2π/5

So, the product of z₁ and z₂ will be:

$z_{1} z_{2} =4*3(cos( \frac{ \pi }{3}+\frac{2 \pi }{5})+isin( \frac{ \pi }{3}+\frac{2 \pi }{5})) \\ \\ 
z_{1} z_{2} =12(cos( \frac{11 \pi }{5}+isin( \frac{11 \pi }{5}))$

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3 years ago

2 is less than x, and 8 is greater than or equal to x

Ksivusya [100]

Awnser:

$2 < x \leqslant 8$

Step-by-step explanation:

2 Is less then x

x is less then or equal to 8

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3 years ago