Answer:
448
Step-by-step explanation:
55 Divided by 880 is 448
Answer:
0.5625 ft^2
Step-by-step explanation:
area of square = side * side
A = s^2
A = (0.75 ft)^2 = (0.75 ft)(0.75 ft) = 0.5625 ft^2
Answer:
The z score for bolt of diameter 18.12 mm is 1.20.
Step-by-step explanation:
Let <em>X</em> = diameter of bolts.
It is provided that the random variable <em>X</em> follows a Normal distribution with mean, <em>μ</em> = 18 mm and standard deviation, <em>σ</em> = 0.10 mm.
A <em>z</em>-score is a standardized score, a numerical, that defines how far a data value from the mean.
The distribution of <em>z</em>-scores is defined by the Standard Normal distribution.

The formula to compute the <em>z</em>-score is:

The value of the diameter of a bolt is, <em>x</em> = 18.12 mm.
Compute the <em>z</em>-score for this value as follows:

Thus, the z score for bolt of diameter 18.12 mm is 1.20.
Answer:
a. 1 1/2 (or 3/2)
b. 2/3
c. 1
d. 1
Step-by-step explanation:
Part A: (1,1) (7,5)
To determine the slope, you will use the equation m=(y2-y1)/(x2-x1). Keep in mind that it doesn't matter what point you use for (x1, y1) or (x2, y2).
Let's plug in the numbers for part a:
m=(7-1)/(5-1)
Let's then solve the problems inside the parentheses:
m=6/4
And finally, we simplify:
m=3/2 (or 1 1/2 depending on what your teacher wants for an answer)
For these others, I will just go through the steps and not explain them, if you need help or don't understand something I'm doing, either look back at what I did for part a or comment on this answer.
Part B: (1,1) (5,7)
m=(5-1)/(7-1)
m=(4/6)
m=2/3
Part C: (2,5) (-1,2)
m=(-1-2)/(2-5)
m=(-3/-3)
m=1
Part D: (2,5) (-7,-4)
m=(-7-2)/(-4-5)
m=(-9/-9)
m=1
Hello!
So, we know that the length of the rectangular basketball court is 84 ft, and the width is 50 ft.
The formula for perimeter of a rectangle is:
P = 2l + 2w
This means that we need to multiply the length by two and the width by two as well.
Substitute:
P = 2(84) + 2(50)
P = 168 + 100
P = 268 ft
ANSWER:
The perimeter of the basketball court is 268 feet long.