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balu736 [363]
3 years ago
7

If a source radiates sound uniformly in all directions and you triple your distance from the sound source, what happens to the s

ound intensity at your new position?
a. The sound intensity drops to 1 / 27 of its original value.b. The sound intensity increases to three times its original value.c. The sound intensity drops to 1 / 3 of its original value.d. The sound intensity drops to 1 / 9 of its original value.e. The sound intensity does not change.
Physics
1 answer:
disa [49]3 years ago
7 0

Sound intensity (energy) falls inversely proportional to the square of the distance  from the sound:

I \propto \frac{1}{r^2}

Therefore if we have two values of intensities we have

\frac{I_1}{I_2} = \frac{r_2^2}{r_1^2}

As we have that

r_1 = 3 r_2

Then we have that

\frac{I_1}{I_2} = \frac{r_2^2}{(3r_2)^2}

\frac{I_1}{I_2} = \frac{1}{9}

Therefore the correct answer is D. The sound intensity drops to 1 / 9 of its original value.

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A proton and an electron are released from rest, with only the electrostatic force acting. Which of the following statements mus
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Their kinetic energy will increase but potential energy will decrease.

Explanation:

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We know that ,electron have negative charge and proton have positive charge it means that they will attract to each other.We know that opposite charge attract to each other and same charge repels to each other.

It means that the velocities of proton and electron will increase and that leads to increase in the kinetic energy of proton and electron.

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So when r will decrease then U will increase but in negative direction it means that U will decrease.

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Consider three vectors A⃗ ,B⃗ and C⃗ all lying in the xy plane. Vector A⃗ has length 6.2 and makes an angle of 131 degrees with
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A) 2.09

B) -62.09°

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Six Resistors Are Connected As Shown In Fig. 2.24. If A Battery Having An E.M.F. Of 24 Volts And Internal Resistance Of 1 S2 Is
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(I) The Current From The Battery is 3A.

(Ii) P.D. across 8 ohm and p.d across 4 ohm is 12V and 3V respectively.

(Iii) The Current Taken From The Battery If A Conductor Of Negligible Resistance Is Connected In Parallel With 8Ω is 6A

<h3>What is current?</h3>

The current is the stream of charges which flow inside the conductors when connected across the end of voltage.

From the Ohm's law, V =IR

R = V/I

Here, R is the proportionality constant.

i)

The resistance 4Ω and 2Ω are in series, So their equivalent is 4+2 =6Ω.

The 6Ω and 6Ω are in parallel, so  their equivalent is 6x6/6+6 = 3Ω.

The  3Ω and 5Ω are in series, so their equivalent is 3 +5 = 8Ω.

The 8Ω and 8Ω are in parallel, so their equivalent is 8x8/8+8 = 4Ω.

The 4Ω and 3Ω are in series, so their equivalent is 4 +3 = 7Ω

The 7Ω and 1Ω are in series,  so their equivalent is 7+1 =8Ω

So, the total equivalent resistance is 8Ω.

The current from the battery is  I =V/Req

I  = 24/8 = 3A

Thus, the current from the battery is 3A.

II) Applying the mesh analysis in three loops, we have

-24 +1 i1 +3i1 +8(i1-i2) =0

12 i1 -8i2 =24..................(1)

5 i2 +6(i2 - i3) +8(i2 -i1) = 0

-8 i1 +19 i2 -6 i3 =0........................(2)

2 i3 +4 i3 +6( i3 - i2) =0

-6 i2 +12 i3 =0...................(3)

On solving these equations, we get

i1 = 3A

i2 = 1.5A

i3 = 0.75A

p.d across 8 ohm = V8 =(i1 - i2) x 8 = 12V

p.d across 4 ohm = V4 = i3 x 4 = 3V

Thus, the p.d across 8 ohm and p.d across 4 ohm is 12V and 3V respectively.

iii)The resistance 2 and 4 ohm are in series, them equivalent is 2 +4 =- 6 ohm

The 6 and 6 ohm are in parallel, so their equivalent is 6x6/6+6 = 3 ohm

The 3 and 5 ohm are in series, so their equivalent is 3 +5 = 8 ohm.

Now 8 ohm is in parallel with a short circuit path. Whenever a short circuit  appears , current will flow through it. So resistance  cant be taken into consideration.

Then, Req = 3+1 ohm = 4 ohm

The current flow will be

I = 24/4 = 6 A.

Thus, The Current Taken From The Battery If A Conductor Of Negligible Resistance Is Connected In Parallel With 8 ohm is 6A.

Learn more about current.

brainly.com/question/10677063

#SPJ1

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