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NeTakaya
3 years ago
7

Here is more points drip students - drip king

Physics
2 answers:
Mars2501 [29]3 years ago
6 0

Answer:

Hewo baby deku here

Explanation:

Thank chu for the points

I'll give u some too! :3

levacccp [35]3 years ago
4 0
Answer
Thanks
Explanation
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What would you do to improve the precision of an experiment?
GenaCL600 [577]

Explanation:

Precision represents that how close the different measurements of the sample one take are to one another.

  • One can increase the precision in lab by paying attention to each and every detail.
  • Usage of the equipment properly and also increasing the sample size.
  • Ensuring that the equipment is calibrated properly. They should be clean and functioning. Using equipment which is not functioning correctly can cause results to swing wildly and also bits of the debris stuck to the equipment can influence the measurements of the mass and the volume.
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3 years ago
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Two objects with a mass of 10,000-kg each and a distance of 1 meter between them.
Fofino [41]

Answer:

d) What is the force if we doubled both the masses AND we doubled the distance

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How many miles away is the sun to the earth?
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<span>92.96 million mi..........</span>
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A student standing on a stationary skateboard tosses a textbook with a mass of mb = 1.25 kg to a friend standing in front of him
juin [17]

Answer:

The velocity of the student has after throwing the book is 0.0345 m/s.

Explanation:

Given that,

Mass of book =1.25 kg

Combined mass = 112 kg

Velocity of book = 3.61 m/s

Angle = 31°

We need to calculate the magnitude of the velocity of the student has after throwing the book

Using conservation of momentum along horizontal  direction

m_{b}v_{b}\cos\theta= m_{c}v_{c}

v_{s}=\dfrac{m_{b}v_{b}\cos\theta}{m_{c}}

Put the value into the formula

v_{c}=\dfrac{1.25\times3.61\times\cos31}{112}

v_{c}=0.0345\ m/s

Hence, The velocity of the student has after throwing the book is 0.0345 m/s.

3 0
3 years ago
Calculate the speed of an 8.0x10^4 kg airliner with a kinetic energy of 1.1x10^9 j ...?
Over [174]
Kinetic energy is the energy possessed by an object on motion. it is expressed as follows:

KE = 0.5mv^2

where m is the mass and v is the velocity of the object. We calculate as follows:


KE = 0.5mv^2
1.1x10^9 J = 0.5(8.0x10^4 kg) v^2
v = 165.83 m/s
6 0
3 years ago
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