A 35 kg child goes down a playground that is inclined at an angle of 27.5 degrees above the horizontal. Find the acceleration if
1 answer:
Answer:
4.16m/s²
Explanation:
According to Newtons second law;
Fm is the moving force
is the coefficient of kinetic friction between the child and the slide
m is the mass
g is the acceleration due to gravity
a is the acceleration of the child
Substitute the given values and get the acceleration as shown;
35(9.8)sin27.5 - 0.415(35)(cos27.5) = 35a
158.38-12.88 = 35a
145.49 = 35a
a = 145.49/35
a = 4.16m/s²
Hence the acceleration of the body is 4.16m/s²
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Answer:
The maximum speed of sonic at the bottom of the hill is equal to 19.85m/s and the spring constant of the spring is equal to (497.4xmass of sonic) N/m
Energy approach has been used to sole the problem.
The points of interest for the analysis of the problem are point 1 the top of the hill and point 2 the bottom of the hill just before hitting the spring
The maximum velocity of sonic is independent of the his mass or the geometry. It is only depends on the vertical distance involved
Explanation:
The step by step solution to the problem can be found in the attachment below. The principle of energy conservation has been applied to solve the problem. This means that if energy disappears in one form it will appear in another.
As in this problem, the potential and kinetic energy at the top of the hill were converted to only kinetic energy at the bottom of the hill. This kinetic energy too got converted into elastic potential energy .
x = compression of the spring = 0.89
