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timofeeve [1]
3 years ago
15

DIVIDE 54.8 by 2.6 and round the quotient to a whole number

Mathematics
1 answer:
OlgaM077 [116]3 years ago
3 0

Answer:

21

Step-by-step explanation:

54.8/2.6=21.0769230769

21.0769230769 rounded would be 21

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I am a 2-digit number. The sum of my two digits is 14. I have more tens than ones. write two numbers I can be.
beks73 [17]
86 and 95; 8+6=14 and 9+5 also =14. The tens value for both of these numbers are also higher than their ones place.
7 0
3 years ago
You owe four people $7 each. Yesterday you paid off your debt. Write two equations to show how much money you paid yesterday
Mademuasel [1]
7+7+7+7=28
7x4= 28
If you are learning multiplication you can use those
4 0
3 years ago
Find the value of x.​
Julli [10]

Answer:

x=4

Step-by-step explanation:

The two given triangles, triangle (BDE) and triangle (BAC) share the angle (<B) in common. Moreover, their bases, line (DE), and line (AC) are parallel, this means that through the corresponding angles postulate, angles (<BDE) and (<BAC) are congrunet. Moreover, angles (<BED) and (<BCA) are also congruent. Thus, triangles (BDE) and (BAC) are similar through angle-angle similarity.

The ratio between the corresponding sides of similar triangles is the same. Therefore, one can form the following equation,

\frac{BD}{BA}=\frac{BE}{BC}.

Substitute,

\frac{BD}{BD+DA}=\frac{BE}{BE+EC}\\\\\frac{x+2}{x+x+2}=\frac{3}{3+2}

Simplify,

\frac{x+2}{2x+2}=\frac{3}{5}

Cross products,

5(x+2)=3(2x+2)\\

Simplify, distribute, multiply every term inside the parenthesis by the term outside of it,

5x+10=6x+6

Inverse operations,

5x+10=6x+6\\\\10=x+6\\\\4=x

5 0
3 years ago
On February 10, 1990, high tide in Boston was at midnight. The water level at high tide was 9.9 feet; later, at low tide, it was
Verizon [17]

Answer:

a) Model

H(t)=4.9cos(\frac{\pi}{6}t)+5

b) The tide will be at 6.5 ft high at 2:24 am (going down).

As the tide will rise again, the tide will be again at 6.5 ft high at 9:36 am (going up).

c) H(10 am) = 7.45

H(4 pm) = 2.55

Step-by-step explanation:

We can model this as a sine or cosine wave, for which we will calculate its parameters by the data given.

The model we will use is:

H(t)=Acos(\omega t+\phi)+B

t will be in hours, starting from midnight (t=0)

1) We know that at midnight happens the high tide. That means that

H(0)=Acos(\omega* 0+\phi)+B=A+B=9.9\\\\ \phi=0\\\\A+B=9.9

2) Six hours later (t=6) happens the low tide (0.1 ft)

H(0)=Acos(\omega*6)+B=-A+B=0.1\\\\\\ cos(\omega*6)=-1,\, \omega=\pi/6\\\\\\B=0.1+A=9.9-A\\\\2A=9.9-0.1\\\\A=9.8/2=4.9\\\\\\B=0.1+A=0.1+4.9=5

Now that we have calculated all the parameters, the model for the height of the tide is:

H(t)=4.9cos(\frac{\pi}{6}t)+5

On Feb 10, when is the water level 6.5 feet high?

H(t)=4.9cos(\frac{\pi}{6}t)+5=6.5\\\\cos(\frac{\pi}{6}t)=(6.5-5)/4.9=0.306\\\\t=\frac{6}{\pi}arcos(0.306)=2.4

The tide will be at 6.5 ft high at 2:24 am (going down).

As the tide will rise again, the tide will be again at 6.5 ft high at 9:36 am (going up).

On Feb 10, what is the water level at 10 am? 4pm?

At 10 am is t=10:

H(10)=4.9cos(\frac{\pi}{6}10)+5=4.9*0.5+5=2.45+5=7.45

At 4 pm, is t=12+4=16

H(16)=4.9cos(\frac{\pi}{6}16)+5=4.9*(-0.5)+5=-2.45+5=2.55

3 0
3 years ago
Margret charges $60 for 2 hours of math tutoring. Lindsay chargers $100 for 4 hours of math tutoring who offers a better deal.
jarptica [38.1K]

Answer:

I think its lindsay

Step-by-step explanation:

if you divide 100 by 4 you get, 25 an hour. (Lindsay's charge)

but if you divide 60 by 2, you get 30 an hour. (Margret's charge.)

5 0
3 years ago
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