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lys-0071 [83]
4 years ago
8

A box plot is known as a box-and-mustache plot? Trueor False??

Mathematics
2 answers:
vladimir1956 [14]4 years ago
6 0
This will be false a box plot is also known as quantile plots
m_a_m_a [10]4 years ago
6 0
False definitely because it called a box-and-whisker plot! Hope that helps I am in Geometry so I've been through all of that.
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Please help me find area of circle
Savatey [412]

Answer:

12.568m^2

Step-by-step explanation:

A=πr^2 where r is. radius

=3.142(2^2)

=3.142(4)

=12.568m^2

5 0
3 years ago
Last week, Clay wrote 4 checks for $20 each from his checking account., withdrew another $30, and finally made a deposit of $96.
Aliun [14]
(4x20)+30=$110 taken out. if he had $96 put back in, then go $110-$96, leaving a balance of -$14, or in other words, the balance dropped $14.
6 0
3 years ago
Please help just tell if the answers are reasonable or not DONT find the real correct answer.
enot [183]

Answer:

annna

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
X+2=-12<br><br> Help ASAP!<br> PLEASE!
Lena [83]

Hey there!

Answer = -14

Explanation:

Let's solve your equation step-by-step.

x + 2 = -12

Subtract 2 from both sides:

x + 2 - 2 = -12 - 2

x = -14

So therefore, that is how you found your answer: x = -14

5 0
3 years ago
A group of college students built a self-guided rover and tested it on a plane surface. They programmed the vehicle to move alon
makkiz [27]

Answer:

B. 40 meters

Step-by-step explanation:

— Estimating

The rectangle enclosing the path has sides of length 9 m and 14 m, so its perimeter is 2(9+14) = 46 m. The distance covered will be shorter than that.

The distance from A to C is longer than the distance from D to C, so we know the distance will be longer than 2·14+9 = 37 m.

Only one answer choice fits in the range 37 < d < 46.

____

— Detailed calculation

The distance from B to C is the hypotenuse of a right triangle with sides 9 and 12. You will recognize that these side lengths are 3 times the side lengths of a 3-4-5 right triangle, so the hypotenuse distance is 3·5 = 15 meters.

The circuit length is ...

AB +BC +CD +DA = 2 + 15 + 14 + 9 = 40 . . . . meters

4 0
3 years ago
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