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KatRina [158]
2 years ago
6

Find BC. PLEASEEE HELP

Mathematics
1 answer:
Cerrena [4.2K]2 years ago
3 0

Answer:

Concept: Geometric Identities

  1. We want BC
  2. We will use geometric identities to get our value
  3. We have BA and AC and angle !A
  4. Hence arccos(89)= 21/x
  5. Hence X=25 km B
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13.5

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Find a compact form for generating functions of the sequence 1, 8,27,... , k^3
pantera1 [17]

This sequence has generating function

F(x)=\displaystyle\sum_{k\ge0}k^3x^k

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\displaystyle\frac{(1-x)^2+2x(1-x)}{(1-x)^4}=\sum_{k\ge0}k^2x^{k-1}=\frac1x\sum_{k\ge0}k^2x^k

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Take the derivative one more time:

\displaystyle\frac{(1+2x)(1-x)^3+3(x+x^2)(1-x)^2}{(1-x)^6}=\sum_{k\ge0}k^3x^{k-1}=\frac1x\sum_{k\ge0}k^3x^k

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\boxed{F(x)=\dfrac{x+4x^3+x^3}{(1-x)^4}}

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Now, the specific event is all shaded marbles or labeled with a multiple of 3. With this specific characteristics 6 marbles, because there are 5 shaded marbles and 6 is a multiple of 3. So, the possible events are 6.

Therefore, the probability is

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