There are two ways to do this but the way I prefer is to make one of the equations in terms of one variable and then 'plug this in' to the second equation. I will demonstrate
Look at equation 1,

this can quite easily be manipulated to show

.
Then because there is a y in the second equation (and both equations are simultaneous) we can 'plug in' our new equation where y is in the second one

which can then be solved for x since there is only one variable

and then with our x solution we can work out our y solution by using the equation we manipulated

.
So the solution to these equations is x=-2 when y=6
Answer:
x1= -7 , x2 = 7
Step-by-step explanation:
x^2 = 37 +12
x^2 = 49
x = -7 or 7
Answer:
See below for answers and explanations
Step-by-step explanation:
4! = 4*3*2*1 = 24
0! = 1
2! + 3! = 2*1 + 3*2*1 = 2 + 6 = 8
3! * 4! = 3*2*1 * 4*3*2*1 = 6 * 24 = 144
10! / 7! = 10*9*8*7*6*5*4*3*2*1 / 7*6*5*4*3*2*1 = 10*9*8 / 1 = 720
Answer:
Step-by-step explanation:
The given polynomial is :
p(x) = 5-10x
We need to find the zeros of the above polynomial. To find it, put p(x) = 0
5-10x = 0
Subtract 5 from both sides
5-10x-5=0-5
-10x=-5
or
10x=5
Divide both sides by 10.
x = 0.5 = 1/2
Hence, the zeros of the polynomial is 1/2.
Answer:
4(x+2) = 4x + 8
Step-by-step explanation:
because if they are multiplied out it would be 4x+8 = 4x + 8 which means it is infinite because both sides are equal