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Natalija [7]
3 years ago
12

Solve (x+y)^2,if x=-1/2 and y=-3

Mathematics
1 answer:
Mariulka [41]3 years ago
8 0

Answer:

\frac{49}{4}

Step-by-step explanation:

In the expression (x+y)^2 we need to replace x and y with the numerical values given, and evaluate. Notice that since one of them is in fraction form, most likely the answer is also expected in fraction form.

When we perform the addition of the two quantities, recall to write both of them with the same denominator, so a simple addition can be performed. That is: write 3 with denominator 2: 3=\frac{6}{2}

Now the evaluation:

(x+y)^2=(\frac{1}{2}+3)^2=(\frac{1}{2}+\frac{6}{2} )^2=(\frac{7}{2}) ^2=\frac{49}{4}

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If you don't know the first derivative of \cot, but you do for \sin and \cos, you can derive the former via the quotient rule:

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or if you know the derivative of \tan:

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Answer:

Step-by-step explanation:

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